Projectile Motion Problem: Calculating Velocity, Distance, and Potential Energy

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Homework Help Overview

The problem involves a projectile motion scenario where a 45.0 kg projectile is launched at a 30.0° angle and remains airborne for 48.0 seconds before returning to the same height. The original poster seeks to determine the projectile's initial velocity, horizontal distance traveled, and potential energy at the peak of its trajectory.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the symmetry of projectile motion and the relationship between time and vertical velocity. Questions arise regarding the determination of vertical acceleration and its relation to gravity.

Discussion Status

Some guidance has been provided regarding the calculation of initial vertical velocity and horizontal distance, with participants exploring the implications of gravitational acceleration on the projectile's motion. Multiple interpretations of the problem setup are being considered.

Contextual Notes

There is uncertainty regarding the understanding of vertical acceleration and its derivation from the given parameters. The original poster expresses a lack of familiarity with projectile motion concepts, indicating a potential gap in foundational knowledge.

Flanery
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Homework Statement


"A 45.0 kg projectile is fired from a gun. The elevation angle of the gun is 30.0°. the projectile is in the air for 48.0 s before it hits the deck at the same height as it was fired. Ignoring friction find: the projectile's initial velocity, the horizontal distance the projectile traveled, and the potential energy of the projectile at it's highest point in its trajectory.

Weight: 45 kg
Angle of launch: 30°
Total time in air: 48 s

Homework Equations


[tex]D = VT[/tex]

The Attempt at a Solution


We haven't done projectile motion problems since the beginning of the year. It seems this problem is a random one on the homework assignments. I've completely forgotten how to calculate these. I drew out the motion of it but it's not ringing any bells.
 
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Welcome to PF!

By symmetry, you know that the time it takes to reach the max height is half of the total travel time (think about it if you're not sure).

Since you know the vertical acceleration, and the time taken to reach the max height (i.e. the time needed to reduce the vertical velocity to zero), you can determine the initial vertical velocity.

Since you know the angle of launch, you can use the above result to determine the initial horizontal velocity, and from that, the total initial velocity.

Once you know the horizontal speed, you can figure out the total horizontal distance travelled.

The max height comes from basic kinematics. You already know the time taken to reach it, and the acceleration.

I hope this helps.
 
cepheid said:
Since you know the vertical acceleration, and the time taken to reach the max height (i.e. the time needed to reduce the vertical velocity to zero), you can determine the initial vertical velocity.

Hey, thanks for your response! I don't quite understand how I have the vertical acceleration. Do I need to find it from the weight/gravity/time?
 
Flanery said:
Hey, thanks for your response! I don't quite understand how I have the vertical acceleration. Do I need to find it from the weight/gravity/time?

What defines projectile motion is that the particle is solely under the influence of gravity. That's the only force that acts on it. So, the vertical acceleration is due to gravity.
 

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