1. The problem statement, all variables and given/known data The center of a baseball of diameter 8.20 cm is 1.320 m vertically above the plate when it is hit. The blast sends it off at an angle of 30.5° above the horizontal with an unknown initial speed. The outfield fence is 94.0 m away and 11.20 m tall: the ball just clears it. Ignoring aerodynamic effects, what was the initial speed of the baseball? 2. Relevant equations -d=vt for the x direction -any free fall equation for the y direction 3. The attempt at a solution dx= 94.0m dy= 9.88m (subtracted the height in which the ball was hit at) Vx= vcos(30.5 Viy=? t= 94.0/vcos(30.5 a= -9.8m.s^2 d=vit+1/2at^2 9.88=vi(94.0/vcos(30.5)-4.9(94.0/vcos(30.5)^2 v^2(-99.22)= -58323.769 v^2= 5884.13 v=76.7m/s where am i going wrong in this problem? help will be greatly appreciated, thanks!