Projectile Motion baseball Problem

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SUMMARY

The discussion centers on solving a projectile motion problem involving a baseball hit at a height of 1.30 m. The baseball travels alongside a wall, clearing it 1.1 seconds after being hit and dropping below it 3.9 seconds later, covering a horizontal distance of 42 m. Key equations used include r(t) = r0 + v0t + 1/2 at². The main challenge identified is accurately determining the initial horizontal velocity (v0) and understanding the timing of the ball's trajectory relative to the wall.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations, specifically r(t) = r0 + v0t + 1/2 at²
  • Basic knowledge of horizontal and vertical motion components
  • Ability to interpret motion graphs and timing in projectile problems
NEXT STEPS
  • Calculate the initial horizontal velocity (v0) using the correct time intervals
  • Explore the effects of different launch angles on projectile motion
  • Investigate the role of air resistance in real-world projectile motion
  • Learn about the trajectory of projectiles in varying gravitational fields
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators seeking to clarify concepts related to kinematics.

J-dizzal
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Homework Statement


In the figure, a baseball is hit at a height h = 1.30 m and then caught at the same height. It travels alongside a wall, moving up past the top of the wall 1.1 s after it is hit and then down past the top of the wall 3.9 s later, at distance D = 42 m farther along the wall. (a) What horizontal distance is traveled by the ball from hit to catch? What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's velocity just after being hit? (d) How high is the wall?

http://edugen.wileyplus.com/edugen/...u/ch0/EAT_13496164302600_3698173899564502.GIF

Homework Equations


r(t)=r0+v0t+1/2 at2

The Attempt at a Solution


im having trouble finding v0 in the x direction I am getting 15m/s=42m/2.8s
[/B]
20150628_121738_zps9yo8uleq.jpg
 
Last edited:
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J-dizzal said:

Homework Statement


In the figure, a baseball is hit at a height h = 1.30 m and then caught at the same height. It travels alongside a wall, moving up past the top of the wall 1.1 s after it is hit and then down past the top of the wall 3.9 s later, at distance D = 42 m farther along the wall. (a) What horizontal distance is traveled by the ball from hit to catch? What are the (b) magnitude and (c) angle (relative to the horizontal) of the ball's velocity just after being hit? (d) How high is the wall?

http://edugen.wileyplus.com/edugen/...u/ch0/EAT_13496164302600_3698173899564502.GIF

Homework Equations


r(t)=r0+v0t+1/2 at2

The Attempt at a Solution


im having trouble finding v0 in the x direction I am getting 15m/s=42m/2.8s[/B]

Your calculations already contain an error.

The ball initially clears the top of the wall 1.1 s after it is hit, according to the problem statement. The ball then travels 42 m before it drops below the top of the wall, 3.9 s later.

You have assumed that the ball drops below the top of the wall 3.9 s after it is hit, which I don't think is what the problem says happens. :wink:
 
SteamKing said:
Your calculations already contain an error.

The ball initially clears the top of the wall 1.1 s after it is hit, according to the problem statement. The ball then travels 42 m before it drops below the top of the wall, 3.9 s later.

You have assumed that the ball drops below the top of the wall 3.9 s after it is hit, which I don't think is what the problem says happens. :wink:
that should help. let me try this again. thanks
 

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