Projectile Motion shot over a cliff

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SUMMARY

A projectile is launched from a cliff 125 meters high with an initial speed of 105 m/s at a 37-degree angle. The time taken for the projectile to hit the ground is calculated to be 5.05 seconds using the formula t=sqrt(2h/g), where g is the acceleration due to gravity (9.81 m/s²). The horizontal range from the base of the cliff is determined to be 530 meters. Further calculations are required to find the horizontal and vertical components of the velocity just before impact, as well as the overall magnitude and angle of the velocity vector.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic knowledge of trigonometry
  • Ability to apply gravitational acceleration in calculations
NEXT STEPS
  • Calculate the horizontal component of velocity using Vx = V * cos(θ)
  • Calculate the vertical component of velocity using Vy = V * sin(θ) - g * t
  • Determine the magnitude of the velocity vector using the Pythagorean theorem
  • Find the angle of the velocity vector with the horizontal using tan(θ) = Vy / Vx
USEFUL FOR

Students studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of objects in motion under the influence of gravity.

sw3etazngyrl
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1. A projectile is shot from the edge of a cliff 125m above ground level with an initial speed of 105m/s at an angle of 37.0 degrees with the horizontal. a) Determine time taken by projectile to hit point P at ground level. b) Determine range X of the projectile as measured from the base of cliff. At the instant just before the projectile hits point P, find c) the horizonal and vertical components of its velocity, d) the magnitude of the velocity, and e) the angle made by the velocity vector with the horizontal.

2. For c, how do you find the vertical/horizontal components? Should I use my answer for a to complete part c?

3. a) t=sqrt(2h/g)=sqrt(2*125m/9.81m/s^2)=5.05 s
b) x=105m/s * 5.05s=530 m

that's all i have so far. i don't know how to start c and the rest after that.
 
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