Projectile Motion : The Impossible Problem

In summary, the problem involves two balls - one thrown up from the edge of a 6.00 m building and one dropped from the roof 2 seconds later. The goal is to find the initial velocity and height of the building that will result in both balls hitting the ground at the same time. By manipulating equations of motion, a general expression can be derived to solve for the initial velocity and height. Additionally, the concept of average acceleration and velocity is used to find vmax and vmin, which have physical interpretations.

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  • #1
tennisame6060
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Homework Statement



A ball is thrown straight up from the edge of the roof of a building. a second ball is dropped from the roof 2 seconds later.

a) if the height of the building is 6.00 m, what must be the initial speed of the first ball if both are to hit the ground at the same time?

consider the same situation but now let the initial speed of the first ball be given and treat the height of the building as an unknown

b) what must be the height of the building be for both balls to reach the ground at the same time for each of the following values of initial velocity:
i) 13.0 m/s
ii) 19.2 m/s

c) if initial velocity is greater than some value vmax, there is no value of h for which both balls hit the ground at the same time. solve for vmax. the value of vmax has a simple physical interpretation. what is it?

d) same question as part c except we are looking for an initial velocity some vmin below which there is no value of h for which both balls hit the ground at the same time. solve for this vmin and give the physical interpretation


Homework Equations



vf2 = v02 + 2a (y-y0)

average acceleration = change in velocity / change in time
average velocity = change in position / change in time

y = y0+vy0t - (1/2)gt2

vf = v0 +at

x-x0= ((v-v0)/2)t


The Attempt at a Solution



clues from the professor: find a general expression combining some basic projectile formulas relating height of the building and initial velocity somehow using times t and t+2 seconds to combine some of these equations, to solve for a, then manipulate to solve for b, and manipulate again to solve for c and d. Sorry guys I thought i had solved a but I think made an error in logic, so posting what i have so far would probably confuse you further.
 
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  • #2


For a the speed that it comes back down to the edge of the building is the same speed it was thrown up at (ignoring air resistance).
So you have a ball dropped and 2sec later one thrown down - just play with the equations of motion
 
  • #3
Okay, so let's start by writing an expression for the position of the first ball at time t. Can you do that?

Edit: Threads merged.
 

1. What is projectile motion?

Projectile motion is the motion of an object that is projected into the air and then moves under the influence of gravity. It follows a curved path known as a parabola.

2. What factors affect projectile motion?

The factors that affect projectile motion include the initial velocity, the angle at which the object is launched, air resistance, and the force of gravity.

3. Can projectile motion be predicted accurately?

In theory, yes. However, in reality, projectile motion is considered an "impossible problem" because it involves the perfect combination of multiple variables, making it impossible to predict with 100% accuracy.

4. How is projectile motion used in real life?

Projectile motion is used in many real-life applications, such as sports (e.g. throwing a ball, shooting a basketball), launching rockets, and even in the design of roller coasters.

5. Can the trajectory of a projectile be altered?

Yes, the trajectory of a projectile can be altered by changing the initial velocity, the angle of launch, or the force of gravity acting on it. However, these changes may not always be predictable due to the complexity of the problem.

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