Projectile Motion : The Impossible Problem

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SUMMARY

The discussion revolves around solving a physics problem involving projectile motion, specifically the scenario where one ball is thrown upwards from a building while another is dropped two seconds later. To determine the initial speed required for both balls to hit the ground simultaneously from a height of 6.00 m, participants utilize kinematic equations such as y = y0 + vy0t - (1/2)gt². Additionally, they explore the maximum initial velocity (vmax) beyond which no height allows simultaneous impact and the minimum initial velocity (vmin) below which the same condition holds. The problem emphasizes the need to derive general expressions that relate height and initial velocity through time variables.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with projectile motion concepts
  • Knowledge of acceleration due to gravity (g = 9.81 m/s²)
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Study kinematic equations for projectile motion in detail
  • Learn how to derive expressions for time of flight in projectile motion
  • Explore the concept of maximum and minimum velocities in projectile scenarios
  • Practice solving complex projectile motion problems with varying initial conditions
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators looking for problem-solving strategies in teaching these concepts.

difficulty

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  • Poll closed .
tennisame6060
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Homework Statement



A ball is thrown straight up from the edge of the roof of a building. a second ball is dropped from the roof 2 seconds later.

a) if the height of the building is 6.00 m, what must be the initial speed of the first ball if both are to hit the ground at the same time?

consider the same situation but now let the initial speed of the first ball be given and treat the height of the building as an unknown

b) what must be the height of the building be for both balls to reach the ground at the same time for each of the following values of initial velocity:
i) 13.0 m/s
ii) 19.2 m/s

c) if initial velocity is greater than some value vmax, there is no value of h for which both balls hit the ground at the same time. solve for vmax. the value of vmax has a simple physical interpretation. what is it?

d) same question as part c except we are looking for an initial velocity some vmin below which there is no value of h for which both balls hit the ground at the same time. solve for this vmin and give the physical interpretation


Homework Equations



vf2 = v02 + 2a (y-y0)

average acceleration = change in velocity / change in time
average velocity = change in position / change in time

y = y0+vy0t - (1/2)gt2

vf = v0 +at

x-x0= ((v-v0)/2)t


The Attempt at a Solution



clues from the professor: find a general expression combining some basic projectile formulas relating height of the building and initial velocity somehow using times t and t+2 seconds to combine some of these equations, to solve for a, then manipulate to solve for b, and manipulate again to solve for c and d. Sorry guys I thought i had solved a but I think made an error in logic, so posting what i have so far would probably confuse you further.
 
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For a the speed that it comes back down to the edge of the building is the same speed it was thrown up at (ignoring air resistance).
So you have a ball dropped and 2sec later one thrown down - just play with the equations of motion
 
Okay, so let's start by writing an expression for the position of the first ball at time t. Can you do that?

Edit: Threads merged.
 

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