SUMMARY
The discussion centers on calculating the time a projectile, fired at 300 m/s at a 45-degree angle, remains in the air under the influence of gravity (-9.8 m/s²) without air resistance. The initial horizontal and vertical velocity components are determined as ViX = 212 m/s and ViY = 212 m/s, respectively. The maximum displacement reached is 2293 m, calculated using the formula vf² = vi² + 2a(d). The time of flight is derived from the vertical motion equations, specifically using the condition that vertical velocity (Vy) equals zero at the peak of the trajectory.
PREREQUISITES
- Understanding of projectile motion principles
- Familiarity with trigonometric functions (sine and cosine)
- Knowledge of kinematic equations for motion
- Basic algebra skills for rearranging equations
NEXT STEPS
- Study the derivation of the time of flight formula for projectile motion
- Learn how to apply the kinematic equation dy = vi(t) + 1/2 a(t)² effectively
- Explore the impact of air resistance on projectile motion
- Investigate the use of vector components in two-dimensional motion analysis
USEFUL FOR
Students in physics, educators teaching projectile motion concepts, and anyone interested in mastering kinematic equations and vector analysis in motion problems.