Projectile Motion/ Velocity Question

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SUMMARY

The discussion focuses on a physics problem involving projectile motion from a helicopter rising at a uniform velocity of 14.70 m/s. The object is projected horizontally with a velocity of 8.50 m/s from a height of 196.00 m. The key equations used include the kinematic equation for vertical motion, specifically 9.8t² + 14.7t - 196 = 0, to determine the time until the object reaches the ground, its horizontal displacement, and its vertical velocity upon impact.

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MAddyG
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Homework Statement



You are piloting a helicopter which is rising vertically at a uniform velocity of 14.70 m/s. When you reach 196.00 m, a large object is projected with a horizontal velocity of 8.50 m/s from the rising helicopter.


Homework Equations



a) When does the ball reach ground level?
b) Where does the ball fall horizontally relative to the helicopter’s position?
c) What is the vertical velocity when it hits the ground?

The Attempt at a Solution



9.8t(squared) + 14.7t -196 = 0
 
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You should find the time it takes to reach the ground first.
 
MAddyG said:

The Attempt at a Solution



9.8t(squared) + 14.7t -196 = 0

Welcome to Physics Forums.

It looks like you are trying to use one of the kinematic equations,

x = xo + vot + (1/2) a t2

However, the expression you wrote has some errors as written. You are on the right track, just be more careful in substituting values into the equation. In particular, think about whether certain quantities (position, velocity, acceleration) should be positive or negative.
 

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