Projectile Motion, With out numbers

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Homework Help Overview

The problem involves projectile motion, specifically determining the angle of projection when the horizontal range is three times the maximum height. The original poster expresses difficulty in starting the problem and lacks specific equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants suggest looking up formulas for horizontal range and maximum height, and then establishing a relationship between them. Others propose breaking the motion into components and analyzing the equations of motion to find when the vertical position returns to zero.

Discussion Status

Some guidance has been offered regarding the use of formulas and component analysis. The original poster indicates they have reached a conclusion, but the discussion reflects varying approaches without explicit consensus on the method used.

Contextual Notes

The original poster mentions a lack of knowledge regarding relevant equations, which may affect their ability to engage fully with the problem. There is also an indication that the problem may be more complex if certain formulas are not available.

hockeyboy
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Projectile Motion, With out numbers :(

Homework Statement



A body is projected at an angle such that the horizontal range is equal to three times the greatest height. find the angle of projection.

Homework Equations


I don't know


The Attempt at a Solution



all i got so far is that vx= v cos(angle) and vy= v sin(angle)

This is a really tricky question for me and i do not know where to start.
 
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You should be able to look in your text for formulas for horizontal range (R) and max height (h). Use thes formulas to write R = 3 h, and then solve for projection angle theta.

If you don't have these formulas, the problem is a bit longer...
 


Split in into components. x(t)=vx*t, y(t)=vy*t-(1/2)*g*t^2. Find the range by figuring out when y(t)=0. The height is where y(t) is a maximum. Where is that?
 


ah. i got it. thanks so much. my final answer was 53.13 degrees.
 

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