Projectile problem (This is a quickie)

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gcombina
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Hello, I need help on my basic math

This is the problem
A projectile is launches with 200kg.m/s of momentum and 1000 J of kinetic energy. What is the mass of the projectile.
(a) 20 kg

This is my math:

P = mv so
m = P/v
m = (200 kg.m/s)/v

KE = 1000 J
1000 J = 1/2 mv ^2
1000 J = 1/2 (mv) v
1000 J = 1/2 (200) v
v = 10 J

IF m = 200/v
m= (200 kg.m/s)/ (10 J)
m= (200 kg.m/s) / (10 NM)
m = (200 kg.m/s) / (10 ma.m)
m = (200 kg.m/s) / (10 kg.m/s.m)
m = (20/m) WHY IS THAT I HAVE THIS ANSWER?? 20/M? Instead of 20kg?
 
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gcombina said:
1000 J = 1/2 mv ^2
1000 J = 1/2 (mv) v
1000 J = 1/2 (200) v
v = 10 J
You forgot that the 200 has units of kg*m/s so when you divide Joules by kg*m/s you get m/s
So the answer is v=10 m/s

gcombina said:
m= (200 kg.m/s)/ (10 J)
m= (200 kg.m/s) / (10 NM)
m = (200 kg.m/s) / (10 ma.m)
m = (200 kg.m/s) / (10 kg.m/s.m)
m = (20/m) WHY IS THAT I HAVE THIS ANSWER?? 20/M? Instead of 20kg?

Now try it with 10 m/s instead of 10 J and see if it works out.
 
when I divide J/(kg*m/s), I get m/s? how so??

isn't J = NM?

so it would be [(nm) / (kg*m/s )] ?
 
gcombina said:
when I divide J/(kg*m/s), I get m/s? how so??

isn't J = NM?

so it would be [(nm) / (kg*m/s )] ?

Yes, and a Newton is [itex]kg*m/s^{2}[/itex] so a Joule is [itex]kg*m^{2}/s^{2}[/itex]
So divide [itex]kg*m^{2}/s^{2}[/itex] (Joules) by [itex]kg*m/s[/itex] and what do you get?
 
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@nascent Oxygen

I am sorry , I do not understand ...what is fs? what is mas?
 
@nathaneal,
thanks!
 
gcombina said:
@nascent Oxygen

I am sorry , I do not understand ...what is fs? what is mas?
These are equations you must commit to memory. They are your tools of trade.

W=F.s where F is force & s is displacement (both F and s are vectors).

F=m.a where F is force & a is acceleration (both a anf F are vectors).