Projectile Stone Off Cliff question

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SUMMARY

The discussion focuses on calculating the horizontal distance a stone travels after being thrown horizontally from a height of 75.7 meters at a speed of 14.0 m/s. The method involves first determining the vertical velocity using the formula v = √(2gh) and calculating the time taken for the stone to reach the ground. The horizontal distance is then calculated by multiplying the horizontal speed by the time of flight. This approach provides a clear solution to projectile motion problems involving horizontal throws from a height.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with basic physics formulas, specifically v = √(2gh)
  • Knowledge of horizontal and vertical velocity components
  • Ability to perform calculations involving acceleration due to gravity (g)
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  • Learn how to derive and apply the equations of motion for vertical and horizontal components
  • Explore real-world applications of projectile motion in sports and engineering
  • Practice solving similar problems involving different initial velocities and heights
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of projectile motion and its calculations.

badboyben03
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A stone is thrown horizontally at 14.0 m/s from a cliff 75.7 m high. How far from the base of the cliff does the stone strike the ground?
 
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Hi,

This is how u go about with the problem:

First calculate the vertical velocity of the stone using
v = & radic ;(2*g*h) and then calculate the time taken t for the ball to reach the ground vertically, then using the horizontal velocity that is given to be = 14m/s by using t = 75.7/vand then calculate the horizontal distance traveled by the stone using 14 * t. This the distance traveled by the stone away from the base of the cliff.


Sridhar
 
Reformatted reply,

Since the answer was not formatted properly, here's the same answer formatted again...
This is how u go about with the problem:
First calculate the vertical velocity of the stone using
v = √(2*g*h) and then calculate the time taken t for the ball to reach the ground vertically, then using the horizontal velocity that is given to be = 14m/s by using t = 75.7/vand then calculate the horizontal distance traveled by the stone using 14 * t. This the distance traveled by the stone away from the base of the cliff.


Sridhar
 
hi

what does g and h stand for?
 


Originally posted by badboyben03
what does g and h stand for?

Perhaps you need to spend a little more time studying, and less time on the computer. We do not do your homework for you here. We make every effort to help you learn, some things you simply must learn on your own. This question says, to me, that you have not put much effort into this assignment. Please set down and read you book.
 
hmmm

ummm...before you talk **** about me, i just want to let you know this isn't my homework. i haven't learned this yet. I am still on acceleration and velocity...so yeah.
 

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