Projectile Trajectory (I'm confused about the lab report)

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Homework Help Overview

The discussion revolves around a lab experiment involving projectile motion, specifically measuring the muzzle velocity of a ball fired from a spring gun and determining its trajectory using data collected at various heights. Participants are attempting to use the quadratic equation to find the final landing point of the projectile.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing how to apply the quadratic equation to determine the final x position (Xp) of the projectile when y equals zero. There are questions regarding the initial conditions and the interpretation of variables such as X0 and v0. Some participants are also clarifying the relationship between height and distance in the context of the problem.

Discussion Status

There is a mix of understanding and confusion among participants. Some have offered suggestions on using the diagram to find constants for the quadratic equation, while others express uncertainty about the variables involved. A few participants indicate they are beginning to grasp the problem, but explicit consensus on a method has not been reached.

Contextual Notes

Participants are working under the constraints of a lab report requirement, which includes plotting the trajectory in Excel and using specific equations to analyze the data. There is mention of needing to clarify the initial conditions and the setup of the experiment.

bedizzy
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The experiment was to measure muzzle velocity of a ball fired by a 'spring gun'. Then to use the equations of projectile motion in order to determine the projectile trajectory. During the experiment we used a variable-height platform to stop the ball mid-air (at y = 0.4 m & y = 0.1 m). Now we're suppose to use the data to determine the final landing point of the trajectory. I have all my data, and I've created the projectile trajectory in excel from the initial position to y = 0.10 m.

Now I'm lost on how to complete the trajectory!? The professor wants us to use the quadratic equation to solve for Xp (Xp is the final point of impact, where y = 0). But I don't know what information to plug into the quadratic equation. And even if I did, it doesn't make sense to me because the range should just be v0 * t.

Can somebody please nudge me in the right direction? If I'm not explaining this clearly, please let me know and I'll post my lab data sheet. I just need to know how to complete this trajectory using the quadratic equation to solve for xp.
 
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I couldn't understand the problem very well. I think that with y, you mean the height above ground.. And that should make x along the ground.. what is X0??
please be more clear!
 
!kx! said:
I couldn't understand the problem very well. I think that with y, you mean the height above ground.. And that should make x along the ground.. what is X0??
please be more clear!
sorry, x0 is suppose to be v0... I just corrected it...

And yes, Y is the height above the ground. The initial y position was 1.20 m. After the projectile was fired, we used a platform to stop the ball at ya = 0.4 m, and yb = 0.1 m. Using experimental data and projectile motion equations I determined xa and xb.

When the ball hits the ground I know that y = 0, but I don't know how to find the x position (Xp).

The professor wants us to show the final trajectory on an excel chart, and told us to use the quadratic equation to solve for xp.

I attached the diagram from my lab report.
 

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The problem is pretty straight forward.. First of all you should know about the quadratic equation you are talking about..
Your diagram gives you 2 points on the curve.. that should help you find the constants in your quadratic equation.. After you get the equation in complete form, with only x,y variables, substitute the last point (y=0,x=?) to get the result..
 
finding range shouldn't be a problem if you know initial velocity and time taken for trajectory.. but that way, you won't be able to plot the trajectory, as you require.
 
!kx! said:
The problem is pretty straight forward.. First of all you should know about the quadratic equation you are talking about..
Your diagram gives you 2 points on the curve.. that should help you find the constants in your quadratic equation.. After you get the equation in complete form, with only x,y variables, substitute the last point (y=0,x=?) to get the result..


I think I got it; the numbers make sense and the chart looks good. I think my problem was that I forgot how to use the slope in the quadratic equation.

Thanks for the help, I really appreciate it...
 

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