Using quadratic formula to find time [projectile motion]

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SUMMARY

The discussion focuses on using the quadratic formula to determine the time of flight for a projectile launched at an angle of 0°. The user initially struggles with the equation ΔY = Viyt + 1/2ayt², specifically when substituting Viy = 0, leading to the equation -4.9t² + 0 + 0.96 = 0. The solution involves correctly applying the quadratic formula to solve for t, confirming that the equation is valid and can be simplified to find the time of flight.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with the quadratic formula
  • Knowledge of kinematic equations for vertical motion
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation and application of the quadratic formula in physics problems
  • Learn about projectile motion equations in different launch angles
  • Explore the effects of initial velocity on projectile trajectories
  • Investigate how to calculate time of flight for various projectile scenarios
USEFUL FOR

Students in physics courses, educators teaching projectile motion, and anyone seeking to understand the application of the quadratic formula in real-world motion problems.

camcognito
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1. Homework Statement
I'm doing lab, and to start we have to find ΔX of a projectile launched an angle. The first step for us is to find time, and to make it easier our teacher recommended us to first set the angle to zero, and find time like that.

I don't have enough X information to find time yet, so I have to use the Y components I think

X
ΔX= .153 M
Φ = 0°
Y
AY = 9.8m/s2
ΔY = -.96 M.
Φ = 0°
Viy = 0 ?

Homework Equations


I'm supposed to take the equation ΔY = Viyt + 1/2ayt2 and make it into quadratic formula. For some reason t = √2ΔY/AY won't work and we're supposed to use quadratic formula

The Attempt at a Solution


[/B]
Since I'm launching the projectile from 0°, I thought the Viy would equal 0. However, when I try to plug that into the quadratic formula, there's a 0 for one of the variables and it doesn't work.

I'm getting -4.9t2 + 0 + .96 = 0; I think I'm doing something wrong in the middle but I'm not sure what to fix.
 
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camcognito said:
1. Homework Statement
I'm doing lab, and to start we have to find ΔX of a projectile launched an angle. The first step for us is to find time, and to make it easier our teacher recommended us to first set the angle to zero, and find time like that.

I don't have enough X information to find time yet, so I have to use the Y components I think

X
ΔX= .153 M
Φ = 0°
Y
AY = 9.8m/s2
ΔY = -.96 M.
Φ = 0°
Viy = 0 ?

Homework Equations


I'm supposed to take the equation ΔY = Viyt + 1/2ayt2 and make it into quadratic formula. For some reason t = √2ΔY/AY won't work and we're supposed to use quadratic formula

The Attempt at a Solution


[/B]
Since I'm launching the projectile from 0°, I thought the Viy would equal 0. However, when I try to plug that into the quadratic formula, there's a 0 for one of the variables and it doesn't work.

I'm getting -4.9t2 + 0 + .96 = 0; I think I'm doing something wrong in the middle but I'm not sure what to fix.

The equation -4.9t2 + 0 + .96 = 0 is correct, just solve it for t.
 
ehild said:
The equation -4.9t2 + 0 + .96 = 0 is correct, just solve it for t.
Wow... it was that simple. Thanks, I've been overthinking a lot of equations recently
 

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