Projectiles launched from platforms of different elevation.

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The discussion focuses on calculating the initial velocity of a projectile launched from a height of 3.2 meters at a 20-degree angle, landing 100 meters away. Participants utilize constant acceleration equations, specifically v = vo + at, x = xo + vo t + ½ a t^2, and v^2 = vo^2 + 2a(x - xo), to derive the solution. The initial velocity is estimated to be between 35 and 40 m/s, although this method is criticized as being imprecise. Clarification is sought regarding the influence of the launch height on the calculations.

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1."A ball is kicked from a platform 3.2m above the ground at an angle of 20 degrees above the horizontal. If the ball lands on the ground 100m away, what is the initial velocity of the ball?" There is no air resistance acting upon the ball and we have to use constant acceleration equations.



2. v = vo + at
x = xo + vo t + ½ a t^2
v^2 = vo^2 + 2a(x - xo)

3. The farthest that I've been able to get is that it is between 35 and 40 but that is only by guess and check which is not an acceptable method. Any input helps. Thanks!
 
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Hi Vikings,

Is it the height of the platform that is confusing you? In other words, would you be able to solve the problem if the platform were at ground height?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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