Projectiles launched horizontally

  • Thread starter rachelx46
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  • #1
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okay so heres the problem..

the fastest recored pitch in MLB was thrown by nolan ryan in 1974. if this pitch were thrown horizontally, the ball would fall 0.809 m by the time it reached the home plate, 18.3 m away. how fast was this pitch?

the book suggests the equation
delta y = -1/2g(deltat)squared

we just started this lesson and i'm really not sure what variable represents what in this problem :confused:
 

Answers and Replies

  • #2
Hootenanny
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If you simply want to know how to use the formula, then the variables are as follows;

y is the vertical displacement
g is the acceleration due to gravity
Δt is the time of flight
 
  • #3
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well, would it be .809=-1/2(g)(t)squared, what else are you supposed to do with this? like where does the horizontal displacement go
 
  • #4
Hootenanny
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rachelx46 said:
well, would it be .809=-1/2(g)(t)squared, what else are you supposed to do with this? like where does the horizontal displacement go
That's right. You now need to solve for the time of flight t. You can then use this together with the horizontal displacement to find the initial velocity.
 
  • #5
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ahh im completely lost now i tried to isolate teh unknwon (t) from the rest of the problem and got t= the square root of 2(delta y)/-g

but the book says that is only for when delta y is negative. can someone explian this problem to me step by step? im reallly confused.
 

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