Projectiles launched horizontally

  • Thread starter rachelx46
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In summary, the conversation is about determining the speed of a pitch thrown by Nolan Ryan in 1974, based on the given information that the pitch would fall 0.809 m by the time it reaches the home plate, which is 18.3 m away. The formula suggested by the book is delta y = -1/2g(deltat)squared, with y representing vertical displacement, g representing acceleration due to gravity, and Δt representing time of flight. The conversation then progresses to discussing how to use the formula to solve for the time of flight and eventually the initial velocity. However, the person is confused about the steps and variables involved.
  • #1
rachelx46
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okay so here's the problem..

the fastest recored pitch in MLB was thrown by nolan ryan in 1974. if this pitch were thrown horizontally, the ball would fall 0.809 m by the time it reached the home plate, 18.3 m away. how fast was this pitch?

the book suggests the equation
delta y = -1/2g(deltat)squared

we just started this lesson and I'm really not sure what variable represents what in this problem :confused:
 
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  • #2
If you simply want to know how to use the formula, then the variables are as follows;

y is the vertical displacement
g is the acceleration due to gravity
Δt is the time of flight
 
  • #3
well, would it be .809=-1/2(g)(t)squared, what else are you supposed to do with this? like where does the horizontal displacement go
 
  • #4
rachelx46 said:
well, would it be .809=-1/2(g)(t)squared, what else are you supposed to do with this? like where does the horizontal displacement go
That's right. You now need to solve for the time of flight t. You can then use this together with the horizontal displacement to find the initial velocity.
 
  • #5
ahh I am completely lost now i tried to isolate teh unknwon (t) from the rest of the problem and got t= the square root of 2(delta y)/-g

but the book says that is only for when delta y is negative. can someone explian this problem to me step by step? I am reallly confused.
 

1. What is a projectile launched horizontally?

A projectile launched horizontally refers to an object that is launched or thrown horizontally with a constant velocity and no initial vertical velocity. This means that the object only moves along the horizontal axis and does not experience any upward or downward motion.

2. What factors affect the horizontal launch of a projectile?

The horizontal launch of a projectile is affected by the initial velocity, the angle of launch, and the force of gravity. The initial velocity and angle of launch determine the horizontal distance the projectile will travel, while the force of gravity affects the time it takes for the projectile to hit the ground.

3. How does the horizontal launch of a projectile relate to its vertical motion?

The horizontal launch of a projectile is independent of its vertical motion. This means that the initial horizontal velocity does not change throughout the motion, while the vertical velocity changes due to the influence of gravity.

4. How can we calculate the horizontal distance traveled by a projectile?

The horizontal distance traveled by a projectile can be calculated using the equation d = v0t, where d is the horizontal distance, v0 is the initial velocity, and t is the time of flight. This assumes that there is no air resistance or other external forces acting on the projectile.

5. What are some real-life examples of projectiles launched horizontally?

Some examples of projectiles launched horizontally include a baseball thrown by a pitcher, a bullet shot from a gun, and a stone skipped across a pond. These objects follow a parabolic path due to the influence of gravity, but their initial launch is horizontal.

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