Projectiles launched horizontally

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Homework Help Overview

The problem involves a projectile motion scenario where a baseball is pitched horizontally, and the vertical displacement due to gravity is considered as it travels towards home plate. The context is rooted in kinematics, specifically analyzing the effects of gravity on a horizontally launched object.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula for vertical displacement and express confusion regarding the variables involved, particularly how to incorporate horizontal displacement into the analysis.

Discussion Status

Some participants have provided clarifications on the variables in the equation, while others are attempting to manipulate the formula to isolate time of flight. There is an ongoing exploration of how to connect vertical and horizontal components of the motion, with no clear consensus reached yet.

Contextual Notes

Participants note confusion regarding the interpretation of negative displacement and the implications of the book's guidance on the equation used for vertical motion. There is an acknowledgment of the challenge in integrating horizontal displacement into their calculations.

rachelx46
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okay so here's the problem..

the fastest recored pitch in MLB was thrown by nolan ryan in 1974. if this pitch were thrown horizontally, the ball would fall 0.809 m by the time it reached the home plate, 18.3 m away. how fast was this pitch?

the book suggests the equation
delta y = -1/2g(deltat)squared

we just started this lesson and I'm really not sure what variable represents what in this problem :confused:
 
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If you simply want to know how to use the formula, then the variables are as follows;

y is the vertical displacement
g is the acceleration due to gravity
Δt is the time of flight
 
well, would it be .809=-1/2(g)(t)squared, what else are you supposed to do with this? like where does the horizontal displacement go
 
rachelx46 said:
well, would it be .809=-1/2(g)(t)squared, what else are you supposed to do with this? like where does the horizontal displacement go
That's right. You now need to solve for the time of flight t. You can then use this together with the horizontal displacement to find the initial velocity.
 
ahh I am completely lost now i tried to isolate the unknwon (t) from the rest of the problem and got t= the square root of 2(delta y)/-g

but the book says that is only for when delta y is negative. can someone explian this problem to me step by step? I am reallly confused.
 

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