Proof: a^3 divides b^2 implies a divides b in Abstract Algebra.

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Homework Help Overview

The discussion centers around a proof in abstract algebra, specifically examining the relationship between two integers \(a\) and \(b\) under the condition that \(a^3\) divides \(b^2\). Participants are exploring the implications of prime factorization in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of prime factorization to establish the relationship between \(a\) and \(b\). Questions arise about how to express the division of primes and the implications of their powers in the factorization.

Discussion Status

There is an ongoing exploration of the implications of the condition \(a^3 | b^2\) and how it relates to the powers of primes in the factorizations of \(a\) and \(b\). Some participants are attempting to clarify their understanding of the necessary conditions for divisibility.

Contextual Notes

Participants are encouraged to consider specific examples to better understand the relationship between \(a\) and \(b\), and there is a focus on the need for clarity in the prime factorization approach. Some participants express uncertainty about the steps needed to progress in their understanding.

stihl29
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Let a, b be integers a,b>0 show that if a^3 | b^2 then a|b
(Consider the prime factorization of a and b)



I've tried setting up generic prime factorization of a and b but then don't get any where, I'm not very strong at this subject.

Any kind of hints / where to start would help a lot thanks!
 
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You already have a perfectly good clue. How did you try to use prime factorization? Show the number of times any prime p divides a is less than or equal to the number of times p divides b.
 
Last edited:
two things, how should i show a prime p, divides a ex.
(p=2^e1 *3^e2 *5^e3...) = a*q?, q is an integer

And why do i need to show that it is less than or equal to the number of times p divides b?
 
stihl29 said:
two things, how should i show a prime p, divides a ex.
(p=2^e1 *3^e2 *5^e3...) = a*q?, q is an integer

And why do i need to show that it is less than or equal to the number of times p divides b?

Let's do the second one first. The only way a can divide b is if the number of times every prime p divides a is less or equal to the number of times p divides b. Think about the prime factorization of b/a. Don't you agree?
 
Dick said:
Let's do the second one first. The only way a can divide b is if the number of times every prime p divides a is less or equal to the number of times p divides b. Think about the prime factorization of b/a. Don't you agree?


yes i agree with what you are saying here.
 
stihl29 said:
yes i agree with what you are saying here.

Well, ok. So then if the largest power of p in a is p^ka and the largest power of p in b is p^kb, what must be true if a^3 divides b^2?
 
do you mean a^3 divides b^2? if so then, b would be larger than a?
 
stihl29 said:
do you mean a^3 divides b^2? if so then, b would be larger than a?

No, I'm asking you to compare the number of times p divides a^3 versus the number of times p divides b^2. The first must be less than or equal to the second, right? What does that tell you about ka and kb?
 
kb must be bigger than ka?
 
  • #10
stihl29 said:
kb must be bigger than ka?

Yes. Why does a^3 divides b^2 tell you that? Please help me here. I can't just tell you what to write down. You have to understand it.
 
  • #11
is it that there is some factor times b that makes a=b?
 
  • #12
stihl29 said:
is it that there is some factor times b that makes a=b?

The best way to start is to just try some simple examples. Make up some small examples which you know will work / not work.

For example, see what happens for a=15 and b=225 (use prime factorization, as hinted).

Now try something like a=15 and b=75. Why doesn't this example work?

See if you can then come up with the general idea.
 

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