Prove that (ax^n)' = nax^n-1 using induction.
I am very weak with induction proof, and I haven't had much trouble proving the basis step, but I can't seem to finish it.....
The Attempt at a Solution
1. Prove (ax)' = a
(a(x+h) - a(x))/h = (ax + ah - ax)/h = (ah)/h = a
2. Prove (ax^n)' = nax^n-1
? I can't seem to get my algebra right....