Proof by integrating Bionomial Theorem

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SUMMARY

The discussion focuses on proving the equation involving the Binomial Theorem, specifically that for any natural number n and real number x, the sum of the series \(\sum_{i=0}^{n} \binom{n}{i} \frac{x^{i+1}}{i+1} = \frac{1}{n+1}((1+x)^{n+1}-1)\). Participants share their attempts to integrate both sides of the Binomial Theorem but express confusion regarding the placement of variables and constants. The integration approach is highlighted as a key method for tackling this proof.

PREREQUISITES
  • Understanding of Binomial Theorem
  • Familiarity with summation notation and combinatorial coefficients
  • Basic knowledge of integration techniques
  • Proficiency in manipulating algebraic expressions
NEXT STEPS
  • Study the properties of the Binomial Theorem in detail
  • Learn integration techniques applicable to series
  • Explore combinatorial proofs and their applications
  • Investigate the relationship between summation and integration in calculus
USEFUL FOR

Mathematicians, students studying calculus and combinatorics, and anyone interested in advanced algebraic proofs involving the Binomial Theorem.

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1. The problem statement,

Prove that for any n[itex]\in[/itex]N and any real umber x,
[itex]\sum\stackrel{n}{i=0}[/itex][itex]\left(\stackrel{n}{i}\right)[/itex][itex]\frac{x^{i+1}}{i+1}=[/itex][itex]\frac{1}{n+1}((1+x)^{n+1}-1)[/itex]


2.
I tried to integrate both sides of Bionomial Theorem
However, I'm not sure what to do at the first place. :(
 
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There are some 0s and ns floating around that I think are misplaced
 

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