Proof - If the square of an integer is even,. .

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If the square of an integer is even, then the integer itself must also be even. To prove this, one can demonstrate that if an integer is odd, its square is also odd, which indirectly supports the original statement. The discussion emphasizes the validity of proof by contradiction, indicating that there is no issue with using this method. Participants suggest exploring definitions of prime numbers and other mathematical principles to aid in understanding. Ultimately, the focus is on establishing the relationship between the evenness of integers and their squares.
yanjt
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Hi,
I have no idea on how to start to do this question.
If the square of an integer is even,then the integer itself is even

I try to check some books but i can't get any similar examples.I wonder if I can directly prove the n=2k, n^2 = 2(2k^2).

Thanks!
 
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But that is the converse of what you were asked to show. You want to show that if m^2 is even, then m is even. One of the definitions of a prime number makes this instantaneous. What definitions of prime do you know?

Alternatively you can show that if n is odd, then n^2 is odd.
 
Welcome to PF!

yanjt said:
Hi,
I have no idea on how to start to do this question.
If the square of an integer is even,then the integer itself is even

I try to check some books but i can't get any similar examples.I wonder if I can directly prove the n=2k, n^2 = 2(2k^2).

Thanks!

Hi yanjt! Welcome to PF! :smile:

Try proving it the other way round:

if an integer is odd, its square is odd. :wink:
 


Prime number is number that can be divided by or itself.
if i prove that an integer is odd,its square is odd,I am not using contradiction to prove it,right?I can show that if an integer is odd,its square is odd.Yet, how can i show that if the square of an integer is even,the integer itself is even?

Thanks for ur help!

p/s:Thanks tiny-tim!I found this website is really useful!=)
 


What's wrong with using proof by contradiction?
 


Nothing is wrong using contradiction.What i mean is that,i wonder if proof "if n is odd,n^2 is odd" is a kind of contradiction?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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