Undergrad Proof of Commutator Operator Identity

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The discussion centers on proving a commutator operator identity relevant to the harmonic oscillator in quantum mechanics. A recommendation is made to use mathematical induction, specifically to prove two simpler statements involving the commutators of the operators. Participants emphasize the importance of posting work directly in the forum instead of images and provide links for assistance with LaTeX formatting. The conversation includes a detailed explanation of how the commutator operates on smooth functions, demonstrating its application in the context of quantum mechanics. Overall, the thread seeks collaborative input to complete the proof effectively.
Peter Yu
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Proof of Commutator Operator Identity used in Harmonic Oscillator of Quantum Mechanics
Hi All,
I try to prove the following commutator operator Identity used in Harmonic Oscillator of Quantum Mechanics. In the process, I do not know how to proceed forward. I need help to complete my proof.
Many Thanks.

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Well, If ##k## is a natural number (which seems to be an asumtion in your proof) I would recommend you to use mathematical induction.
 
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Thank you for your response.
Can you enlighten me on the approach.
 
Do you know what mathematical induction is?
 
Sorry I do not know. Can you give me some hints.
 
Peter Yu said:
Sorry I do not know. Can you give me some hints.
https://en.wikipedia.org/wiki/Mathematical_induction

Essentially, is to prove only two easier statements:
$$\left[\hat{a}^\dagger, \hat{a}\right]=-\hat{a}^0$$ and $$\left[\hat{a}^\dagger, \hat{a}^k\right]=-k\hat{a}^{k-1}\Longrightarrow \left[\hat{a}^\dagger, \hat{a}^{k+1}\right]=-(k+1)\hat{a}^{k}$$
 
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Peter Yu said:
\big[ \hat{a}^{\dagger} , \left( \hat{a}\right)^{k}\big] = - k \left( \hat{a}\right)^{k - 1}
You can easily show that the commutator \big[ \hat{a}^{\dagger} , \hat{a} \big] = -1 has the following representation \hat{a} \to a \ \mbox{id}_{C^{\infty}} , \ \ \hat{a}^{\dagger} \to - \frac{d}{da} ,
acting on the space C^{\infty} of smooth functions of the variable a. So, for any function f(a) \in C^{\infty} and any p \in \mathbb{R}, you have \big[ \hat{a}^{\dagger} , (f(a))^{p} \ \mbox{id}_{C^{\infty}} \big] = - p \ (f(a))^{p-1} \ \frac{df}{da} \ \mbox{id}_{C^{\infty}} .
 
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