Proof of no net gravitational force on a particle inside uniform shell

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Discussion Overview

The discussion revolves around the proof of Newton's shell theorem, specifically addressing the concept that a uniform shell of matter exerts no net gravitational force on a particle located inside it. Participants explore the theoretical implications and seek clarification on the reasoning behind the theorem.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant states that Newton's shell theorem indicates that a uniform shell exerts no net gravitational force on an internal particle.
  • Another participant suggests that the gravitational forces from different parts of the shell cancel each other out, resulting in zero net force.
  • Several participants share links to external resources for further reading on the proof of the shell theorem.
  • A participant expresses confusion about the reasoning behind treating a system of shells as a point mass and questions the division of the spherical shell into infinitesimal shells.
  • Another participant clarifies that the sphere can be considered as an infinite number of spherical shells, each with mass concentrated at the center.
  • There is a discussion about the geometric interpretation of dividing the sphere, with one participant correcting another's misunderstanding regarding the shape of the divisions.
  • A later reply confirms that the centers of the spherical shells lie at the center of the sphere, addressing a participant's confusion about the arrangement of the shells.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the proof and the geometric interpretation of the spherical shells. While some agree on the application of the shell theorem, others remain confused about specific aspects, indicating that the discussion is not fully resolved.

Contextual Notes

Some participants exhibit uncertainty about the division of the sphere into shells and the implications of treating them as point masses. There are unresolved questions regarding the geometric arrangement of the shells and their centers.

AakashPandita
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In my book it is written that Newton's shell theorem can be used to show that a uniform shell of matter exerts no net gravitational force on a particle located inside it. How?
 
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proof?
 
Thanks.
 
Its written on wikia :If one of these shells can be treated as a point mass, then a system of shells (i.e. the sphere) can also be treated as a point mass. I don't understand its reason.

Maybe I don't understand how the spherical shell is divided into infinite shells. Are they shaped like infinitesimally thin rings? If yes then I don't understand the reason of the given statement in bold.
Help!
 
Yes. You have to consider the sphere as infinitesimally number of spherical shell.
 
okay.so?
 
You have to consider the sphere as infinitesimally number of spherical shell. And if you take one spherical shell then the mass of spherical shell consider to be concentrate at the center of shell.. Like that the mass of all the spherical shell to be concentrate at the center of the shell. And finally you will get the total mass of sphere concentrated at the center of the sphere.
 
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  • #10
Hardik Batra said:
Like that the mass of all the spherical shell to be concentrate at the center of the shell.
How?
 
  • #11
because we have considered the sphere as innumerable number of spherical shell, and the center of all shell is at the center of earth
 
  • #12
how? if we take the centers of all the shells they would lie on the diameter.
 
  • #13
AakashPandita said:
how? if we take the centers of all the shells they would lie on the diameter.
Maybe I don't understand how the spherical shell is divided into infinite shells. Are they shaped like infinitesimally thin rings?
I think this is the source of your confusion. You're thinking of dividing the sphere as if you were slicing a tomato - into very thin rings or discs of increasing(and after half-way through, decreasing) diametre, each ring having its centre lying along the radius of the sphere.

What is being done, is dividing the sphere as if you were peeling an onion - into very thin layers, each laying on top of the other. Each layer's centre(the point equidistant from all of its constituent points) lies in the centre of the sphere.
 
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  • #14
Oh ! Thank You! I finally understand.
 

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