Pretty difficult trig proof (identity)

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Homework Help Overview

The discussion revolves around proving a trigonometric identity involving sine, cosine, and cotangent functions. The original poster presents an equation and expresses uncertainty about their progress in simplifying it.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the steps taken by the original poster, questioning the correctness of their manipulation of trigonometric functions. There are requests for clarification on how results were obtained, and some participants express concern about providing direct solutions.

Discussion Status

The conversation is ongoing, with participants offering feedback on the original poster's work and pointing out potential misunderstandings. There is an emphasis on maintaining the learning process without directly solving the problem.

Contextual Notes

Participants note the importance of adhering to forum rules regarding not providing complete solutions, which influences the nature of the guidance offered.

iRaid
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Homework Statement


\frac{sin\theta}{1-cos\theta} - \frac{cot\theta}{1+cos\theta} = \frac{1-cos^{3}\theta}{sin^{3}\theta}


Homework Equations


Trig identities..


The Attempt at a Solution


Basically I got to:
\frac{sin\theta+(cos^{2}\theta)(sin\theta)}{sin^{2}\theta}

Homework Statement



Is that right up to there, I think not because I can't get passed this lol.


Homework Equations





The Attempt at a Solution

 
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That doesn't look right.

Show how you got your result so we can help you.
 
iRaid said:

Homework Statement


\frac{sin\theta}{1-cos\theta} - \frac{cot\theta}{1+cos\theta} = \frac{1-cos^{3}\theta}{sin^{3}\theta}


Homework Equations


Trig identities..


The Attempt at a Solution


Basically I got to:
\frac{sin\theta+(cos^{2}\theta)(sin\theta)}{sin^{2}\theta}

Homework Statement



Is that right up to there, I think not because I can't get passed this lol.


Homework Equations





The Attempt at a Solution


You did notice the cot function did you - or did you misread it as cos?
 
I don't think you were supposed to solve the question for the Original Poster!
 
Last edited by a moderator:
>_> Oh. Well, I hope my explanation blurb thing helps so that I'm not just blatantly giving the solution without providing any real understanding.
 
Dr. Seafood said:
>_> Oh. Well, I hope my explanation blurb thing helps so that I'm not just blatantly giving the solution without providing any real understanding.
PeterO is correct. The Physics Forums rules do not permit a member to post the solution to another member's problem.
 
OK, I attached the rest of my work..
 

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iRaid said:
OK, I attached the rest of my work..

In your 5th line, when you took out a factor of sin(theta) in the numerator, it was not a common factor, as it was in the denominator of a couple of the terms.
 
PeterO said:
In your 5th line, when you took out a factor of sin(theta) in the numerator, it was not a common factor, as it was in the denominator of a couple of the terms.

I see now thanks, I got it. Stupid mistakes.
 

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