Given that [tex]\log{(1+x)}=\int_0^x\frac{dt}{1+t}[/tex], how would one prove that [tex]\lim_{x \to 0}\frac{\log{(1+x)}}{x}=1[/tex]?(adsbygoogle = window.adsbygoogle || []).push({});

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# Proof that lim x->0 log(1+x)/x = 1

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