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Pascal's Pal
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Homework Statement
Prove that log2 of 5 is irrational.
Homework Equations
None.
The Attempt at a Solution
I just had a glimpse of the actual solution, but I'm wondering if mine would work too.
2^(a/b) = 5
square both sides...
2^(2a/b) =25
2 = 25^(b/2a)
(b/2a) = log25 of 2
b = 2aLog25 of 2
b is even...
and through a similar process...by taking the square root of both sides of "2^(a/b) = 5" you can arrive at a being even too. So how can they both be even etc etc.