1. The problem statement, all variables and given/known data Prove that log2 of 5 is irrational. 2. Relevant equations None. 3. The attempt at a solution I just had a glimpse of the actual solution, but I'm wondering if mine would work too. 2^(a/b) = 5 square both sides... 2^(2a/b) =25 2 = 25^(b/2a) (b/2a) = log25 of 2 b = 2aLog25 of 2 b is even... and through a similar process...by taking the square root of both sides of "2^(a/b) = 5" you can arrive at a being even too. So how can they both be even etc etc.