Proofing the Modulation Index for AM Transmission

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Discussion Overview

The discussion revolves around the modulation index for amplitude modulation (AM) transmission, focusing on the mathematical proof and derivation of the modulation index formula. Participants explore the relationships between maximum and minimum voltage values and their implications for the information transmitted.

Discussion Character

  • Technical explanation, Mathematical reasoning, Homework-related

Main Points Raised

  • One participant presents the equations for maximum and minimum voltage in AM transmission and expresses frustration with the mathematical proof process.
  • Another participant suggests that the solution involves solving two simultaneous equations by adding and subtracting them to derive the modulation index.
  • A third participant critiques a link provided as unhelpful, indicating it does not address the original question.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus, as there are differing opinions on the usefulness of external resources and the approach to solving the equations.

Contextual Notes

The discussion includes assumptions about the relationships between voltage values and the modulation index, but these assumptions are not explicitly stated or agreed upon by all participants.

commelion
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ive been trying to proof the modulation index for Am transmission, it goes like this

Vmax = a(1+u)
Vmin = a(1-u)

it basicilly describes the amount of infromation in the total power transmitted and should allways be between 0 & 1

eventually the answer should come out to be

u = (Vmax-Vmin)/(Vmax+Vmin)

its the maths in between that is anoying the hell out of me, if anybody has any info on doing this please help, I've tried matrices so don't bother ! :bugeye:

thanks in advance.
 
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worse than useless response

it does not address the question what so ever, but thanks anyway
 
You just need to solve the two simultaneous equations that you have at the beginning of your first post:
Add them and then subtract them, then take the ratio to get u- it falls out in three lines.
 
ok thanks ill try that
 

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