What Is the Work Required to Accelerate a Proton from 0.5c to 0.7c?

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SUMMARY

The discussion focuses on calculating the work required to accelerate a proton from 0.5c to 0.7c using the work-energy theorem, emphasizing the necessity of accounting for relativistic effects. Participants clarify that the classical kinetic energy formula is inadequate for relativistic speeds, and the correct approach involves using the relativistic kinetic energy equation: KE = mc²((1/sqrt(1-(v²/c²)))-1). The accurate calculation yields a work value of approximately 3.69 x 10-11 joules.

PREREQUISITES
  • Understanding of relativistic physics concepts
  • Familiarity with the work-energy theorem
  • Knowledge of the speed of light (c) and its significance in physics
  • Ability to manipulate algebraic equations and square roots
NEXT STEPS
  • Study the derivation of the relativistic kinetic energy formula
  • Learn about the implications of relativistic speeds on mass and energy
  • Explore examples of work-energy calculations in high-energy physics
  • Investigate how accelerators like the Large Hadron Collider utilize these principles
USEFUL FOR

Students and professionals in physics, particularly those focused on high-energy particle physics, as well as educators teaching concepts related to relativistic mechanics.

SsUeSbIaEs
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Can some one help me out here, I have tried using several different methods but I still don't know what I am doing wrong.

The question is:

A proton in a high energy accelerator moves w/a speed of 0.5c, use the work-energy theorem to find the work required to increase its speed to 0.7c.


I have tried /\K=.5m(vf^2-vi^2), what am I doing wrong?
 
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You're not taking into account relativistic effects.

cookiemonster
 
Ugh!?

I don't know what your talking about,

I thought I would use:

.5m( (.7*c)^2-(.5*c)^2)

c= the speed of light

I was also told an equation like m^2c^2((1/sqrt(1-(v^2/c^2)))-1), but I kept geting zero for my answer and the actual answer is like 3.69??e-11, but I do not know how they got this answer??
 


Originally posted by SsUeSbIaEs
.5m( (.7*c)^2-(.5*c)^2)
This is only correct for low, non-relativistic speeds.
I was also told an equation like m^2c^2((1/sqrt(1-(v^2/c^2)))-1) ...
Use the relativistically correct expression for KE:
KE = mc^2((1/sqrt(1-(v^2/c^2)))-1)
 

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