Proton in Magnetic Field Problem

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SUMMARY

The discussion focuses on calculating the radius of the circular path of a proton moving through a magnetic field. Given the proton's speed of 7.0 x 103 m/s and a magnetic field strength of 0.75 T, the relevant equations are F=qvB and Fc=mv2/r. The charge of the proton is equal to that of the electron but is positive. The oversight regarding the charge value and proton mass was acknowledged, leading to a clearer understanding of the problem.

PREREQUISITES
  • Understanding of magnetic fields and forces
  • Familiarity with the equations of motion in circular paths
  • Knowledge of proton properties, including charge and mass
  • Basic algebra for solving equations
NEXT STEPS
  • Learn how to apply the Lorentz force equation in different scenarios
  • Study the relationship between velocity, magnetic field strength, and radius in circular motion
  • Explore the concept of centripetal force in the context of charged particles
  • Investigate the effects of varying magnetic field strengths on particle trajectories
USEFUL FOR

Students in physics, educators teaching electromagnetism, and anyone interested in the dynamics of charged particles in magnetic fields.

whoopie88
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Homework Statement


A proton moves at a speed of 7.0 multiplied by 103 m/s as it passes through a magnetic field of 0.75 T. Find the radius of the circular path. Note that the charge carried by the proton is equal to that of the electron, but is positive.

Homework Equations


F=qvB
Fc=mv^2/r

The Attempt at a Solution


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Help!
 
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The digits of your charge value look suspiciously like those of the proton mass.
 
Oh wow. I can't believe I overlooked that. Thank you so much!
 

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