Proton moving through magnetic field

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SUMMARY

A proton moving through a uniform magnetic field of (6.97i - 9.54j + 35.0k) mT experiences a magnetic force of (4.72E-17i + 3.45E-17j) N. To find the velocity components vx and vy, the equation F = qV x B is utilized, where the cross product of the velocity vector (vx, vy, 1.58 km/s) and the magnetic field vector is calculated. The resulting cross product yields the equations (35vy + 15.07) = 4.72E-17 and (35vx - 11.07) = 3.45E-17, allowing for the determination of vx and vy through algebraic manipulation.

PREREQUISITES
  • Understanding of vector cross products
  • Familiarity with magnetic force equations (F=qV x B)
  • Knowledge of unit conversions (mT to T)
  • Basic proficiency in algebra for solving equations
NEXT STEPS
  • Learn how to compute vector cross products in three dimensions
  • Study the implications of magnetic fields on charged particles
  • Explore the conversion of millitesla (mT) to tesla (T)
  • Review the principles of Lorentz force in electromagnetism
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Students studying electromagnetism, physics educators, and anyone seeking to understand the motion of charged particles in magnetic fields.

mariahkraft
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Homework Statement



A proton moves through a uniform magnetic field given by =(6.97-9.54+35.0) mT. At time t1, the proton has a velocity given by =vx+vy+(1.58 km/s) and the magnetic force on the proton is FB=(4.72 X 10-17N)+(3.45 X 10-17N).

(a) At that instant, what is vx?

(b) At that instant, what is vy?

Homework Equations


F=qV x B

The Attempt at a Solution



So, in order to find the velocity in the x direction I am assuming you do this:
(4.27E-17)i +(3.45E-17)j=e[(vx+vy+1.58k)x(6.97i-9.54j+35k)]

That is really all I have because I can't figure out the cross product. I end up with vx terms in the j direction and I don't know what to do with them. I hope I am making sense. Please let me know if youcan help. THANK YOU!
 
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Could you please clarify your vector velocity and B-field components? And then show how you derived the vector force components? Please label the x, y, and z components explicitly in each equation.
 
they are given in the problem

b= (6.97i-9.54j+35.0k)

and the vector force was not derives as is also given in the equation as: (vx)i+(vy)j+(1.58 km/s)k
 
You have the field and the charge and the initial veloity. You have what you need. What are the relevant equations?
 
You did leave off the i, j, and k unit vectors when describing the problem which left a little to the imagination. But it looks like your equation:

(4.27E-17)i +(3.45E-17)j=e[(vx+vy+1.58k)x(6.97i-9.54j+35k)]

looks correct so far. Could you show us the cross product you ended up getting so we could see if you did something wrong? And getting a vx term in the j direction is alright. Once you have the cross product, you just equate the i-terms on both sides of the equation, and do the same for the j- and k-terms and solve.
 
for the cross product i got:
(35vy+15.07)i+(35vx-11.07)j+(-9.54vx-6.97vy)k

if I do this:
(4.72E-17)=(35vy+15.07) and I solve for vy that is what the velocity in the x directions is? .431? Why am I solving for vy if i am looking for vx?
 
hmm I bet I need to convert the mT to T huh?
 

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