Prove a rotationally symmetric central force field is conservative

Click For Summary
SUMMARY

The discussion focuses on proving that the rotationally symmetric central force field defined by F(x) = xg(|x|) is conservative. It establishes that F is conservative if there exists a scalar-valued function f such that F = grad(f). The key insight is that since g is continuous, it has an anti-derivative G, and by differentiating G(|x|), one can demonstrate that F is indeed the gradient of the scalar function f. The final conclusion emphasizes the necessity of including the absolute value in the force representation to accurately express the relationship.

PREREQUISITES
  • Understanding of vector calculus, specifically gradients and conservative fields.
  • Familiarity with the concept of anti-derivatives and continuous functions.
  • Knowledge of rotationally symmetric force fields in physics.
  • Experience with integration techniques in multivariable calculus.
NEXT STEPS
  • Study the properties of conservative vector fields in vector calculus.
  • Learn about the relationship between force fields and potential functions in physics.
  • Explore the concept of anti-derivatives and their applications in proving conservativeness.
  • Investigate the implications of rotational symmetry in physical force fields.
USEFUL FOR

Students and professionals in physics and mathematics, particularly those studying vector calculus, force fields, and potential theory.

Ryker
Messages
1,080
Reaction score
2

Homework Statement


Suppose g:(0, +∞) → ℝ is continuous, and consider F:ℝd\{0} → ℝd, where F(x) = xg(|x|). Prove F is conservative.

Homework Equations


F is conservative iff there exists a C1 function f:ℝd\{0} → ℝd, s.t. F = grad(f). (edit: Or is the codomain of f actually ℝ, so that it's a scalar-valued function? I namely may have put it down wrong in class.)

F is conservative if, for every closed rectifiable path ∫Fdx = 0.

The Attempt at a Solution


I tried approaching this problem from both angles, i.e. "relevant equations", and came to the conclusion (might be wrong, of course) that if I'm to prove this the second one won't be of particular help. So I went for the first one and tried to construct the function f.

Here's where I run into problems, though. Since g is continuous, we know it has an anti-derivative, call it G. But...
\frac{\partial G}{\partial x_{i}} = \frac{x_{i} h(|x|)}{|x|} =: H
So the numerator is fine, but I can't get rid of |x|. I then also though of saying that H is conservative, and then showing |x|H is also such. But I can't get anywhere with that, either.

Any help here would be greatly appreciated!
 
Last edited:
Physics news on Phys.org
If g(|x|) is continuous then so is |x|g(x). Call the antiderivative of that G(|x|).
 
And then just differentiate G(|x|) to show that F is indeed grad(f), where f is just G? Is that it or am I missing something? Because if that IS it, then damn I'm slow, I can't believe I didn't arrive to that conclusion myself.
 
Ryker said:
And then just differentiate G(|x|) to show that F is indeed grad(f), where f is just G? Is that it or am I missing something? Because if that IS it, then damn I'm slow, I can't believe I didn't arrive to that conclusion myself.

No, that's all there is to it. And f is a scalar. Force laws are usually written in terms of a unit vector times magnitude, (x/|x|)*m(|x|). Then you can just integrate m. Your form is missing that extra absolute value so you need to put it back in. x*g(|x|)=(x/|x|)*|x|*g(|x|).
 
Thanks a lot!
 

Similar threads

Replies
9
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
6
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K