Prove/Find Counterexample: Intro to Set Theory

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Homework Help Overview

The discussion revolves around a statement in set theory that posits a relationship between sets A, B, and C within a universe U. The original poster is tasked with proving or finding a counterexample to the claim that if the union of A and C contains the union of B and C, then A must contain B.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to provide a counterexample using specific sets, while others suggest clarifying assumptions about the sets involved. Some participants explore the validity of using an element proof to approach the problem.

Discussion Status

The discussion includes various attempts to clarify the original statement and explore counterexamples. Participants are engaging with each other's reasoning, and while some guidance has been offered regarding the assumptions, there is no explicit consensus on the correctness of the approaches discussed.

Contextual Notes

There is a noted emphasis on the necessity of stating that certain sets are not empty, which may affect the validity of the counterexamples being considered. Additionally, there is a mix of approaches, including both counterexamples and proofs, which may lead to confusion regarding the original task.

mbcsantin
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Homework Statement



Prove or find counterexamples. For any sets A, B, C in a universe U:

if A union C contained B union C then A contained B

Homework Equations



none.

The Attempt at a Solution



im just not sure if i did it right. id appreciate if you can check my work and let me know what changes i have to make. thanks

Let A be the empty set, and let B = C
Then A union C = B and
B union C = B so,
A union C contains B union C, but A does not contain B because A is the empty set and B is not.
 
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Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.
 
e(ho0n3 said:
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.

alright. thank you so much!
 
e(ho0n3 said:
Looks right to me. Just one small note: You should state that B = C is not empty at the beginning.

But what if I use the element proof for this..

Supposed that A is a subset of B.

Let x is an element of A u C.
therefore, x is an element of A and x is an element of C.
Since A is a subset of B by the definition of containment, x is an element of B.
Since x is an element of B and x is an element of C, we have x is an element of B u C. so any element of B u C is also in A u C. therefore, A u C is a subset of B u C.

Would this be right?
 
You are giving a counter example. You don't need a general proof, just any single counter example. You could just take A= {}, B= {1}, C= {1}.
 
mbcsantin said:
Let x is an element of A u C.
therefore, x is an element of A and x is an element of C.

No, that implies x is an element of A or x is an element of C.

Anyway, what you did here is irrelevant to your original question.
 

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