Prove identity sec^-1(x) = cos^-1(1/x)

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Homework Help Overview

The discussion revolves around proving the identity sec-1(x) = cos-1(1/x). Participants are exploring the relationship between the secant and cosine inverse functions, questioning the validity of the proposed identity.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants attempt to manipulate the definitions of secant and cosine inverse to establish the identity, while others question the correctness of the identity itself, suggesting it may not hold true for certain values.

Discussion Status

The discussion includes attempts to prove the identity, with some participants expressing skepticism about its validity. There is a recognition of potential errors in reasoning, and participants are exploring different interpretations of the functions involved.

Contextual Notes

Participants note that the identity may not be valid for all values of x, particularly highlighting cases where x is less than 1, which raises questions about the definitions and domains of the functions involved.

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Homework Statement



Find and prove the identity sec^-1(x) in terms of cos^-1(arg) (Note that 1/cos^-1(x) is not equal to sec^-1(x).

Homework Equations



None.

The Attempt at a Solution



sec(sec^-1(x)) = x

1/cos(sec^-1(x)) = x

1/cos(cos^-1(x)) = 1/x

1/cos(cos^-1(1/x)) = 1/1/x = x

cos^-1(1/x) = sec^-1(x).

Is this correct?
 
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physicsernaw said:

Homework Statement



Find and prove the identity sec^-1(x) in terms of cos^-1(arg) (Note that 1/cos^-1(x) is not equal to sec^-1(x).

Homework Equations



None.

The Attempt at a Solution



sec(sec^-1(x)) = x

1/cos(sec^-1(x)) = x

1/cos(cos^-1(x)) = 1/x
How do you justify the previous step?
physicsernaw said:
1/cos(cos^-1(1/x)) = 1/1/x = x

cos^-1(1/x) = sec^-1(x).

Is this correct?
 
The fundamental problem with try to prove "sec^{-1}(x)= cos^{-1}(1/x)" is that it is NOT true! This is NOT an identity. For example, if x= \pi/4 sec^{-1}(x)= \sqrt{2}/2 while 1/x= 4/\pi, cos(1/x)= 3.41, approximately.
 
HallsofIvy said:
The fundamental problem with try to prove "sec^{-1}(x)= cos^{-1}(1/x)" is that it is NOT true! This is NOT an identity. For example, if x= \pi/4 sec^{-1}(x)= \sqrt{2}/2 while 1/x= 4/\pi, cos(1/x)= 3.41, approximately.
\displaystyle \sec(\pi/4)=\sqrt{2}\

\displaystyle \sec^{-1}(\pi/4)\ is undefined, since \displaystyle\ \ \pi/4<1\ .
 
I would be inclined to write sec-1(x) as \displaystyle \ \sec^{-1}\left(\frac{1}{1/x}\right)\,,\ then use the identity, cos(cos-1(u) = u , for the denominator.
 

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