Prove its abelian is this proof correct

  • Thread starter natasha d
  • Start date
  • #1
19
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Homework Statement


(ab)[itex]^{n}[/itex]= a[itex]^{n}[/itex]b[itex]^{n}[/itex] for any 3 consecutive numbers n [itex]\in[/itex]N

Homework Equations


for an abelian group G, ab=ba [itex]\forall[/itex]a,b[itex]\in[/itex]G
if a[itex]\in[/itex]G, a has an inverse element also [itex]\in[/itex]G such that aa[itex]^{-1}[/itex] = e


The Attempt at a Solution


doesnt look right but heres the attempt

http://pics.livejournal.com/jackdnutter/pic/000013d1 [Broken]
 
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Answers and Replies

  • #3
19
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that looks fishy....
yeah it does, which is why I asked. Whats wrong with it though? if someone could point out the flawed reasoning maybe it'd better my understanding of group theory.
Thanks for the link, the (ba)[itex]^{∞}[/itex] proof was hilarious
 

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