Prove sequence diverges to infinity

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SUMMARY

The sequence a(n) = (n^3 - n + 1) / (2n + 4) diverges to infinity as n approaches infinity. For large values of n, the numerator behaves like n^3 and the denominator behaves like 2n. To rigorously prove this divergence, one can perform polynomial long division or synthetic division, which simplifies the expression and reveals that the limit approaches infinity. Completing the square for the resulting quadratic can further solidify the proof.

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Homework Statement



I have to prove that the sequence a(n)=(n^3-n +1)/(2n+4) diverges to infinity.



Homework Equations





The Attempt at a Solution



Observe that n^3-n +1 > (1/2)n^3 and 2n+4≤4n in n≥2

I am now stuck on how to proceed. I am confused on opposite inequalities for the numerator and denom. Can you direct as to how I'm to proceed?

Thanks!
 
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sitia said:

Homework Statement



I have to prove that the sequence a(n)=(n^3-n +1)/(2n+4) diverges to infinity.

Homework Equations


The Attempt at a Solution



Observe that n^3-n +1 > (1/2)n^3 and 2n+4≤4n in n≥2

I am now stuck on how to proceed. I am confused on opposite inequalities for the numerator and denom. Can you direct as to how I'm to proceed?

Thanks!

To "see" it, just observe that for large n, the numerator approaches n3, while the denominator approaches 2n.

To prove it, just do the long division to get a quadratic quotient (and a remainder, which vanishes at the limit). Or use synthetic division. From this point on, the limit should be obvious (although you can complete the square for the quadratic to make it even more rigorous).
 

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