Prove that ##12≤OP≤13## in the problem involving complex numbers

Click For Summary
SUMMARY

The discussion centers on proving that the value of ##OP## lies between 12 and 13 in the context of complex numbers. The participant establishes that ##OP## reaches its minimum value of 12 when ##|z+5|=|z-5|##, corresponding to the endpoints of the minor axis, and a maximum value of 13 at the endpoints of the major axis. The proof utilizes the equation ##|z-5| + |z+5| = 26## and derives that ##OP = |z| = \frac{1}{2}(|z+5| + |z-5|) \leq 13##. Further calculations confirm that ##|z|^2 \geq 144##, leading to the conclusion that ##12 \leq OP \leq 13##.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with geometric interpretations of complex functions
  • Knowledge of inequalities and their applications in complex analysis
  • Ability to manipulate absolute values and algebraic expressions
NEXT STEPS
  • Study the geometric interpretation of complex numbers in the Argand plane
  • Explore the properties of absolute values in complex analysis
  • Learn about inequalities in complex numbers, focusing on triangle inequalities
  • Investigate the implications of the Cauchy-Schwarz inequality in complex contexts
USEFUL FOR

Mathematicians, students studying complex analysis, and anyone interested in geometric interpretations of complex number properties.

chwala
Gold Member
Messages
2,827
Reaction score
415
Homework Statement
See attached.
Relevant Equations
Complex numbers
Find the question below; note that no solution is provided for this question.

1641037770478.png


My approach;
Find part of my sketch here;

* My diagram may not be accurate..i just noted that, ##OP## takes smallest value of ##12## when ##|z+5|=|z-5|## i.e at the end of its minor axis and greatest value ##13## at end of its major axis

1641037915512.png


We have been given,
##|z-5|+(z+5|=26##
Then ##OP=|z|=|\dfrac{1}{2}((z+5)+(z-5))|##
##≤ \dfrac{1}{2}(|z+5|+|z-5|)=\dfrac{1}{2}×26=13##

Also,
##(|z+5|+|z-5|)^2=676## and ##(|z+5|-|z-5|)^2≥0##, adding this two gives us
##2|z+5|^2+2|z-5|^2≥676##
##⇒|z+5|^2+|z-5|^2≥338##
##(z+5)(z^*+5^*)+(z-5)(z^*-5^*)≥338##
##2zz^*+50≥338##
##2zz^*≥288##
##zz^*≥144##, which is ##|z|^2≥144##
##⇒z≥12##, therefore ##12≤OP≤13##
 
Last edited:
Physics news on Phys.org
Looks good.
 

Similar threads

Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 8 ·
Replies
8
Views
1K
Replies
2
Views
2K
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K