Prove that a series converges:

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SUMMARY

The discussion centers on proving the convergence of the series formed by the terms {a_n}^(p/(p+1)) given that the series of positive numbers {a_n} converges. The professor suggests using the comparison test, specifically examining the condition where {a_n}^(1/(p+1)) ≤ 1/2. The participant attempts to validate this approach but encounters a counterexample with a_n = 1/n^2 and p = 1, leading to a divergent series. This indicates that additional conditions may be necessary for the convergence of the transformed series.

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Homework Statement


Let {a_n} be a sequence of positive numbers such that the sum of {a_n} from n = 1 to n = infinity converges. Show that the sum of {a_n} ^ (p / (p + 1)) from n = 1 to n = infinity also converges.


Homework Equations



n/a

The Attempt at a Solution



My professor provided me with some guidance here and I would like to double check and make sure that I'm on the right track. He told me to consider the terms with the sums with the property {a_n} ^ (1 / (p + 1)) <= 1/2. From this series, I believe that the series {a_n} ^ (p / (p + 1)) consisting of these terms would have to converge to 1/2. If all the terms were <= 1/2, then obviously this series would converge via the comparison test because {a_n} ^ (p / (p + 1) <= {a_n} ^ (p / (p +1)).

However, there is the case where {a_n} ^ (1 / (p + 1)) > 1/2. I changed the inequality so it now reads as 1 / ({a_n} ^ (1 / (p + 1))) < 2. Something should work out here but I don't see it at the moment.
 
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That's not even true. Pick a_n=1/n^2. That converges. Pick p=1. (1/n^2)^(1/2)=1/n. That does not converge. Did you forget a premise?
 
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