# Prove that for all real numbers x there is a y n which case x<y

1. Nov 5, 2012

### Andrax

1. The problem statement, all variables and given/known data
prove that
($\forall$x$\in$R) ($\exists$y$\in$R) : x < y

2. Relevant equations

3. The attempt at a solution
x < y
y= x+1
then x<x+1
which is correct but i'm kinda not sure of this answer...

2. Nov 5, 2012

### hedipaldi

y=x+1 satisfies x<y so what wrong with it?

3. Nov 5, 2012

### Andrax

just wanted to make sure someone actually confused me saying it dosen't