Prove the following is a group

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SUMMARY

The discussion focuses on proving that a nonempty set S with an associative binary operation * qualifies as a group, given that for all elements a, b in S, there exist solutions c and d such that a*c=b and d*a=b. The proof requires demonstrating three key properties: associativity (already satisfied), the existence of an identity element, and the existence of inverses for each element in S. The identity element can be identified by showing that c and d serve as the identity for any element a, and proving that c equals d is essential for establishing the identity's uniqueness.

PREREQUISITES
  • Understanding of group theory concepts, specifically the definition of a group.
  • Familiarity with binary operations and their properties.
  • Knowledge of the concept of identity elements in algebraic structures.
  • Ability to manipulate and prove statements involving equations in set theory.
NEXT STEPS
  • Study the properties of identity elements in group theory.
  • Learn how to prove the existence of inverses in algebraic structures.
  • Explore examples of associative binary operations and their implications for group formation.
  • Review the fundamentals of set theory and its application in abstract algebra.
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Students of abstract algebra, mathematicians interested in group theory, and educators teaching algebraic structures will benefit from this discussion.

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Homework Statement


Prove that a nonempty set S with an associative binary operation * on S such that a*c=b and d*a=b have solutions in S for all a,b in S is a group.


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The Attempt at a Solution


In order to prove something is a group, I know that I must show associativity of *, existence of identity element and inverse for each element in S.
- We are given that S has an associative binary operation, so that is satisfied.
- In regards to finding the identity element such that a*e=e*a=a for all a in S...this is where I am not sure where to begin. Any suggestions on how to start?
 
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Take a and b to be the same element a. Then your premise tells you you can find c and d such that a*c=a and d*a=a. It looks like c and d should be your identity 'e', right? To show that's true, you have to prove c=d, and you have to prove if you pick another element besides a, you get the same identity. It can be done. You just have to keep using the only premise you've got over and over. Similar course for inverses.
 

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