Prove the sum equals 0 provided another given sum equals 1

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The discussion establishes that if the equation $\displaystyle \frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}=1$ holds true, then it follows that $\displaystyle \frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}=0$. By substituting the initial condition into the derived equation and simplifying, it is proven that the variable $k$, representing the sum of the squared fractions, equals zero.

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Prove that if $\displaystyle \frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}=1$, then $\displaystyle \frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}=0$
 
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$\dfrac {c}{a+b}+\dfrac{a}{b+c}+\dfrac{b}{c+a}=1----(1)$
let :
$\dfrac {c^2}{a+b}+\dfrac{a^2}{b+c}+\dfrac{b^2}{c+a}=k$
$(1)\times a+(1)\times b+(1)\times c$
we get
k+a+b+c=a+b+c
$\therefore k=0$
 
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