MHB Prove the sum equals 0 provided another given sum equals 1

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The discussion focuses on proving that if the sum of fractions $\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}=1$, then it follows that $\frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}=0$. By multiplying the initial equation by $a$, $b$, and $c$, the result leads to the conclusion that $k + a + b + c = a + b + c$. This simplifies to show that $k$ must equal zero. The proof effectively demonstrates the relationship between the two sums under the given condition. The mathematical reasoning confirms the validity of the statement.
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Prove that if $\displaystyle \frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}=1$, then $\displaystyle \frac{a^2}{b+c}+\frac{b^2}{c+a}+\frac{c^2}{a+b}=0$
 
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$\dfrac {c}{a+b}+\dfrac{a}{b+c}+\dfrac{b}{c+a}=1----(1)$
let :
$\dfrac {c^2}{a+b}+\dfrac{a^2}{b+c}+\dfrac{b^2}{c+a}=k$
$(1)\times a+(1)\times b+(1)\times c$
we get
k+a+b+c=a+b+c
$\therefore k=0$
 
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