Prove Trigonometric Statement: Ideas & Solutions

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    Proof Trigonometric
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Homework Help Overview

The discussion revolves around proving a trigonometric statement involving double angle formulas and identities. Participants are exploring various methods to approach the proof.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential use of double angle formulas and mathematical induction as methods for proof. Some express uncertainty about the applicability of induction, while others share their attempts and suggest alternative identities.

Discussion Status

The conversation is active, with participants sharing different approaches and questioning the effectiveness of mathematical induction. Some have reported progress using specific trigonometric identities, while others are still seeking viable methods.

Contextual Notes

There is mention of the complexity of identities involved and the challenges faced in proving the statement, indicating that the problem may require careful consideration of the chosen methods.

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Have you tried mathematical induction?
 
Metaleer said:
Have you tried mathematical induction?

Hi thanks for the reply,

No, don't know why I didn't think of that,

Will give it a go now.
 
I don't think this is to be done with mathematical induction. I ended up with these massive identities and really long formulas,

Is there another way?
 
I managed to do it using

<br /> \cos a \sin b = (\sin (a+b) - \sin(a-b))/2<br />

PROBLEM SOLVED!
 
Have u proven the P1 case and related Pk with Pk+1?

Do u think the identity below will help ? :wink:

sin(x)cos[(2k+1)x]
=\frac{sin[((2k+2)x)-((2k)x)]}{2} + \frac{cos[((2k+2)x)+((2k)x)]}{2}
=\frac{1}{2}[sin((2k+2)x)-sin((2k)x))]
 

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