Prove Vector Integration: Closed Surface S = 0

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Homework Help Overview

The problem involves proving that the integral of the vector cross product \(\int\int_{S} \mathbf{r} \times d\mathbf{S} = 0\) for any closed surface \(S\). The subject area relates to vector calculus and the application of the divergence theorem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the divergence theorem and question the validity of the original poster's attempts. There is also a clarification regarding the definition of the vector \(\mathbf{r}\) and its relation to the integral being computed.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding the application of the divergence theorem, but there is no explicit consensus or resolution yet.

Contextual Notes

Participants have noted the need for the original poster to provide more of their work to facilitate better assistance. There is an emphasis on the importance of effort in problem-solving within the forum's guidelines.

aj06
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Homework Statement


Prove [tex]\int\int_{S}r \times dS=0[/tex]
for any closed surface S.


Homework Equations





The Attempt at a Solution


i used divergence theorem but i didn't make it...
 
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aj06 said:
i used divergence theorem but i didn't make it...

Well, how far did you make it with that? Show us what you've got and we'll be better able to help you.
 
the value of r= x^2+y^2+z^2
 
aj06 said:
the value of r= x^2+y^2+z^2

First,

[tex]r=||\textbf{r}||=\sqrt{x^2+y^2+z^2}\neq x^2+y^2+z^2[/itex]. <br /> <br /> Second, is this the entirety of your attempt at the problem? What does this have to do with computing the integral<br /> <br /> [tex]\int\int_{\mathcal{S}}\textbf{r}\times d\textbf{S}[/tex]<br /> <br /> ??[/tex]
 
i don't know sir...
 
Try applying the divergence theorem to the vector field [itex]\textbf{c}\times\textbf{r}[/itex], where [itex]\textbf{c}[/itex] is any constant (position independent) vector... What does that give you?
 
thank you sir...
but can i have the complete solution of it sir..
thank you
 
aj06 said:
but can i have the complete solution of it sir..

No. We do not provide complete solutions here. It is unethical and it doesn't really help you learn any problem solving skills.

You need to make some effort and show your work in order to receive further help.
 

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