The discussion revolves around proving the equation x² + y² + z² + w² = 36 for real numbers x, y, z, and w, given a specific condition involving a summation of squares divided by expressions dependent on n, where n takes on the values 2, 4, 6, and 8.
The discussion is ongoing, with participants questioning the initial problem setup and providing guidance on how to approach the problem by substituting values for n. There is no explicit consensus yet on the path forward.
Participants note the need for clarity in the problem statement, particularly regarding the equation that the variables must satisfy, as well as the implications of the values of n used in the context.
radou said:
You're unable to think of anything? The most obvious starting point is substituting n = 2, n = 4, n = 6, and n = 8, and seeing what you get.jeedoubts said:Homework Statement
if the real numbers x,y,z,w satisfy (x2/(n2-1))+(y2/(n2-32))+(z2/(n2-52))+(w2/(n2-72)) = 1 for n=2,4,6,8 then prove
x2+y2+z2+w2=36
Homework Equations
The Attempt at a Solution
unable to think of anything?
That will give you four different equations in four unknowns -- in other words, exactly what is needed to solve the problem.Mark44 said: