- #1

- 11

- 0

I tried a lot, but cant get any answer. Can someone please help me out?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter suhasm
- Start date

- #1

- 11

- 0

I tried a lot, but cant get any answer. Can someone please help me out?

- #2

- 286

- 0

Try:

[tex]x^2 + (y + z)x + (y^2 + z^2 - yz) = 0[/tex] and use the quadratic formula and see where that leads.

--Elucidus

- #3

arildno

Science Advisor

Homework Helper

Gold Member

Dearly Missed

- 10,025

- 134

[tex]\frac{1}{2}x^{2}+\frac{1}{2}x^{2}+\frac{1}{2}y^{2}+\frac{1}{2}y^{2}+\frac{1}{2}z^{2}+\frac{1}{2}z^{2}-xy-xz-zy=0[/tex]

and see if you can make some clever manipulations.

- #4

Mark44

Mentor

- 35,287

- 7,140

- #5

- 286

- 0

--Elucidus

- #6

- 2,044

- 312

y = x + a, and z = x+b.

and ended up with

a^2 + b^2 = ab, where you have to prove that a = b = 0.

- #7

- 1

- 0

y = x + a, and z = x+b.

and ended up with

a^2 + b^2 = ab, where you have to prove that a = b = 0.

A much easier way,

from

x2+y2+z2=xy+yz+zx

you can get

2x2+2y2+2z2=2xy+2yz+2zx

which equals

2x2+2y2+2z2-2xy-2yz-2zx=0

,the equivalant is

(x-y)2+(y-z)2+(z-x)2=0.

Share: