1. Show that a volume of a clyinder equals to v= A^2 \ (4πh) where h= height of the cylinder A = area of a original paper how would i prove this question? could any one please help thank you v= πr^2 h -------1 v=A^2 \ (4πh)-----2 i tried to make h da subject but i got 4v^2 = Ar^2 which it does work out
Since this is in the precalculus forum, i won't refer to integrals. The regular expression for the volume of a cylinder is nr^2h. The area of the paper is A. Find an expression for A in terms of n, r and h, and simply square that and divide by 4nh to show that this equals the volume of the sylinder.
what's the meaning of "A = area of a original paper" yOU skipped the most important part !? by folding a paper to form a cylinder !? I assume.. A=2πrh V=πrrh = 2πrh2πrh\4πh = AA\4πh @.u