Proving absolute values theorems

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Discussion Overview

The discussion revolves around proving the theorem related to absolute values, specifically that for all real numbers \(x\) and \(y\), if \(x + y \ge 0\), then \(|x + y| = x + y\). The scope includes mathematical reasoning and proof techniques.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant asks how to prove that \(|x + y| = x + y\) under the condition \(x + y \ge 0\), noting that their textbook assumes this to be true.
  • Another participant suggests letting \(a = x + y\) and questions what \(|a|\) is, implying a need to explore the definition of absolute value.
  • A later reply reiterates the definition of absolute value and states that since \(a = x + y \ge 0\), it follows from the definition that \(|x + y| = x + y\).

Areas of Agreement / Disagreement

Participants generally agree on the definition of absolute value and its application in this context, but the initial question about proving the theorem remains open without a formal consensus on the proof method.

Contextual Notes

The discussion does not resolve the proof method and relies on the definition of absolute value, which may depend on the participants' understanding of mathematical definitions and proof techniques.

tmt1
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For all real numbers $x$ and $y$ , if $x + y >= 0$ then $|x + y| = x + y$. How would I prove this?

My textbook just assumes this to be true.
 
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Let $a = x+y$. What is $|a|$?
 
Deveno said:
Let $a = x+y$. What is $|a|$?

$|x + y|$
 
tmt said:
For all real numbers $x$ and $y$ , if $x + y >= 0$ then $|x + y| = x + y$. How would I prove this?

My textbook just assumes this to be true.

The absolute value of a real number is defined as:
$$|a| = \begin{cases}a&\text{if } a\ge 0 \\ -a & \text{if } a<0\end{cases}$$

Since it is already given that $a = x+y \ge 0$, it follows from the definition that $|x+y|=x+y$.
 

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