Proving an Axiom: Stuck on Field's Commutativity

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Homework Help Overview

The discussion revolves around proving the axioms of a field, specifically focusing on the commutativity of addition and multiplication within the context of complex numbers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definitions of addition and multiplication for complex numbers and discuss how to demonstrate commutativity. There are attempts to clarify the implications of the definitions used and the structure of the proof.

Discussion Status

Some participants have provided guidance on how to approach the proof, while others have raised questions about the definitions and assumptions involved. The discussion reflects a collaborative effort to refine understanding without reaching a definitive conclusion.

Contextual Notes

There is uncertainty regarding the specific set being used for the proof, although complex numbers are suggested as the context. Participants also mention the definitions of complex numbers and their operations, which may influence the proof structure.

sara_87
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Homework Statement



I was asked to prove the axioms of a field.
so, if we look at the first one:
commutativity: a+b=b+a and a*b=b*a where a and b belong in the set of the field

Homework Equations





The Attempt at a Solution



it's tempting to just substitute values but i know this is the wrong approach since this wouldn't prove the axiom for all values in the set. so I am stuck.
 
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It would help a lot if we knew what the set was.
 
the question just says: prove the axioms of a field.
but the chapter we are studying is complex numbers so maybe i have to prove them for complex numbers. if so, would this proof be good enough:
for: a+b=b+a: where a=u+vi and b=x+yi
u+vi+x+yi=x+yi+u+vi
??
 
mmmmm. I suppose you can't just say that C is isomorphic to R[x]/(x2 + 1) and that because (x2 + 1) is maximal, it must be a field?

How you write the proof depends on how you've defined complex numbers and how you've defined addition and multiplication. Is the definition something like a + bi = (a, b)?
 
what do you mean '(x^2+1) i maximal' here?
yes that's the definition we use for complex numbers.
 
Ok, then what you want to do for commutativity of addition is (a, b) + (c, d) = (a + c, b + d) = (c + a, d + b) = (c, d) + (a, b).

Do you notice how we "got a free ride" once we got a and c in the same tuple? That just reduces to commutativity of the reals, which I assume you can take for granted.

As far as the maximal thing, it just means that the ideal generated by x1 + 1 in the polynomial ring over R isn't contained in any others. You'll probably learn about it if you're taking an algebra class. It was mainly just a joke.
 
:) ok
I understand the proof now.
for a*b=b*a, would this be convincing:
(a,b)*(c,d)=(a+bi)(c+di)=(ac-bd, bc+ad)=(ca-db, cb+da)=(c,d)*(a,b)
 
sara_87 said:
(a,b)*(c,d)=[STRIKE](a+bi)(c+di)[/STRIKE]=(ac-bd, bc+ad)=(ca-db, cb+da)=(c,d)*(a,b)

You don't need to stick the term that I struck out in there. Remember, i is just (0, 1). Other than that, it looks great though.
 
thank you. now i can prove the other axioms.
 

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