Proving C is a Subset of D: Problem Statement & Attempt at Solution

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The discussion centers on proving that the set C, defined as C = {(x, y) ∈ R^2 : y ≥ (x + 2)^2}, is a subset of the set D, defined as D = {(x, y) ∈ R^2 : y ≥ 4x + 4}. The proof demonstrates that for any element (x, y) in C, the inequality y ≥ 4x + 4 holds true. The proof is validated through algebraic manipulation, confirming that y - 4 ≥ 4x is derived from the original inequality. The discussion highlights the simplicity of the problem, emphasizing the importance of clear reasoning in mathematical proofs.

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1. The problem statement.
consider the following sets;
  1. C = {(x, y) ∈ R^2 : y ≥ (x + 2)^2},

    D = {(x, y) ∈ R^2 : y ≥ 4x + 4}.
show that C is a subset of D.

3. Attempt at solution.

Let (x,y) be an arbitrary element of C, then

y ≥ x^2 + 4x + 4.

Rearranging the inequality gives

y - 4 ≥ x^2 + 4x.

Now since x^2 ≥ 0 for all x in R. This implies that

y -4 ≥ 4x. Hence y ≥ 4x+4. As required.

Now my gut instinct is that i am totally wrong with this. I am just starting my degree and usually find these questions quite easy.
I have tried various other manipulations but to no avail :(. If i must be honest i have "forced it".

Note;
I do know this is a simple question and i only just started my degree.
 
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Your proof is fine, although you didn't need to subtract 4 and add it back. You could have just written$$
y\ge (x+2)^2 = x^2 + 4x + 4 \ge 4x + 4$$
 
Thank you so much for the swift reply, PF never fails.
 

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