Proving centripetal acceleration formula

Click For Summary
SUMMARY

The centripetal acceleration formula, expressed as a = v² / r, is derived from the principles of uniform circular motion. By analyzing the position of an object in circular motion using the equations x = r cos(ωt) and y = r sin(ωt), one can compute the speed as v = √(ẋ² + ẏ²) = ωr. The acceleration can then be determined as a = ω²r², leading to the established relationship between velocity, radius, and acceleration. This derivation can also be extended to non-uniform circular motion.

PREREQUISITES
  • Understanding of uniform circular motion
  • Familiarity with calculus, specifically differentiation
  • Knowledge of angular velocity (ω)
  • Basic trigonometric functions (sine and cosine)
NEXT STEPS
  • Research the derivation of centripetal acceleration in non-uniform circular motion
  • Explore the relationship between angular velocity and linear velocity
  • Study the applications of centripetal acceleration in real-world scenarios
  • Learn about the effects of varying radius on centripetal acceleration
USEFUL FOR

Students studying physics, educators teaching circular motion concepts, and anyone interested in the mathematical foundations of motion dynamics.

dragon513
Messages
26
Reaction score
0
Hi I was taught about centripetal accerleration last class, but my teacher didn't tell me why or how this formula works.

So I was wondering if anyone knows a website that has mathematical proof of this formula.

Thanks in advance.
 
Physics news on Phys.org
dragon513 said:
Hi I was taught about centripetal accerleration last class, but my teacher didn't tell me why or how this formula works.

So I was wondering if anyone knows a website that has mathematical proof of this formula.

Thanks in advance.
Have a look at this link:

AM
 
What formula are you talking about?

If you mean a = v^2 / r then you may be able to convince yourself with the following:

If an object is undergoing uniform circular motion then

x = r \cos \omega t

y = r \sin \omega t

Now just take derivatives and find the speed v = \sqrt {\dot x^2 + \dot y^2} = \omega r. Likewise, the acceleration is a = \omega^2 r^2.

Combine the two to obtain

a = \frac {v^2}{r}

You can generalize this to "nonuniform" circular motion.
 
Last edited:

Similar threads

Replies
55
Views
3K
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
7
Views
8K