How to Prove a Group is Cyclic?

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SUMMARY

To prove that a finite group G with cardinality p (a prime integer) is cyclic, start by applying Lagrange's theorem. Since the only subgroups of G are itself and the trivial subgroup {e}, the possible orders of any element g in G are limited to 1 or p. Given that g is not the identity, its order must be p, leading to the conclusion that G can be expressed as {1, g, g², ..., g^(p-1)}, confirming that G is cyclic.

PREREQUISITES
  • Understanding of cyclic groups and their definitions
  • Familiarity with Lagrange's theorem
  • Basic knowledge of group theory
  • Concept of group order and element order
NEXT STEPS
  • Study the implications of Lagrange's theorem in group theory
  • Explore examples of cyclic groups in different mathematical contexts
  • Learn about the structure of finite groups
  • Investigate the relationship between group order and subgroup properties
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Mathematics students, particularly those studying abstract algebra, group theorists, and anyone interested in the properties of finite groups and cyclic structures.

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Homework Statement



How do i go about proving that a group is cyclic?

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The Attempt at a Solution

 
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Start with the definition of a cyclic group, and see if your group satisfies it.
 
The group, G, is a finte group with cardinality p, a prime integer. How should i start off, if i need to prove it's cyclic?
 
Are you familiar with Lagrange's theorem?
 
yes, i know that the only subgroups of G are itself and the subgroup {e} which consists of the neutral element. This is because the only possibilities of the cardinalities of the subgroups are 1 or p.
 
Ok, now pick an element of the group G, say g not equal to 1. What are the possible orders of g?
 
possible orders of g are 1 or p? Since those are the only numbers that divide the prime number p.
 
It cannot be 1 because we assumed g was not equal to the identity. So the order of g must be p, and therefore G = {1 , g, g2, ... , gp-1} which is cyclic.
 
Ok, thanku very much for the help:)
 
  • #10
No problem.
 

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