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If G is cyclic, and G is isomorphic to G', then G' is cycli

  1. Feb 20, 2017 #1
    1. The problem statement, all variables and given/known data
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    3. The attempt at a solution
    This would seem to be very easy problem, since it's intuitively obvious that if two groups are isomorphic, and one is cyclic, then the other is cyclic too. However, I can't seem to formalize it with math.

    Here is an idea. We can define that a group is cyclic by saying that for all b in G, there exists an a such that ##a^n = b## for some integer n. Now if G is cyclic, and we have an isomorphism ##\phi## from G to G', then it is true that ##\phi (a) ^n = \phi (b) = b'##, which means that G' is also cyclic. Does this sketch of a proof the right idea?
     
  2. jcsd
  3. Feb 20, 2017 #2

    fresh_42

    Staff: Mentor

    Yes it is. You can leave out the ##b's## as you don't need them, the generator ##a## is sufficient, i.e. simply write ##a^n##. It doesn't need to be named. And you may forget the isomorphism, surjectivity is sufficient. And subgroups of cyclic groups are also cyclic.
     
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