Proving Even Fct Lim x->0 f(x)=L iff Lim x->0+ f(x)=L

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Homework Help Overview

The discussion revolves around proving a limit property for even functions, specifically that for a function f: R->R, the limit as x approaches 0 of f(x) equals L if and only if the limit as x approaches 0 from the positive side of f(x) equals L.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the even function property, noting that f(x) = f(-x). They discuss applying limit definitions and consider how changing variables might relate to the limits from different sides.

Discussion Status

Participants are actively engaging with the definitions of limits and attempting to clarify the connections between the limits from the positive and negative sides. Some have expressed confusion regarding the organization of their arguments and the application of definitions.

Contextual Notes

There is a focus on the definitions of limits as they relate to the even function property, with participants questioning how to effectively utilize these definitions in their proof. The variable 'a' is noted to be 0 in the context of the limits being discussed.

MathSquareRoo
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Homework Statement


Prove that if f: R->R is an even function, then lim x->0 f(x)=L if and only if lim x->0+ f(x)=L.


Homework Equations





The Attempt at a Solution



So far I have:

If f is an even function f(x)=f(-x) for x in domain of f.

Then I am trying to apply the limit definitions, but am unsure of how to write the proof from here.
 
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MathSquareRoo said:

Homework Statement


Prove that if f: R->R is an even function, then lim x->0 f(x)=L if and only if lim x->0+ f(x)=L.


Homework Equations





The Attempt at a Solution



So far I have:

If f is an even function f(x)=f(-x) for x in domain of f.

Then I am trying to apply the limit definitions, but am unsure of how to write the proof from here.

Write down the definition of lim x->0+ f(x)=L. Now change x to -x. Doesn't it look like the definition of lim x->0- f(x)=L once you use that f is even?
 
So lim x->0+ f(x)=L implies there exists a real number L s.t. epsilon>0 there exists delta>0 s.t. lf(x)-Ll<epsilon provided 0<x-a<delta.

Then lim x->0+ f(-x)=L implies that there exists a real number L s.t. epsilon>0 there exists delta>0 s.t. lf(-x)-Ll<epsilon provided 0<x-a<delta.

I have the definitions, but I don't understand the last part of your comment, can you clarify?
 
MathSquareRoo said:
So lim x->0+ f(x)=L implies there exists a real number L s.t. epsilon>0 there exists delta>0 s.t. lf(x)-Ll<epsilon provided 0<x-a<delta.

Then lim x->0+ f(-x)=L implies that there exists a real number L s.t. epsilon>0 there exists delta>0 s.t. lf(-x)-Ll<epsilon provided 0<x-a<delta.

I have the definitions, but I don't understand the last part of your comment, can you clarify?


'a' in your problem is 0. 0<x<delta, is the same as -delta<-x<0. What does the definition of lim x->0- f(x)=L look like?
 
lim x->0- f(x)=L implies that there exists a real number L s.t. epsilon>0 there exists delta>0 s.t. lf(x)-Ll<epsilon provided 0<a-x<delta.

I'm am getting confused with all these definitions though, can you help me organize the argument using the definitions?
 

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