Proving Grad(F) is perpendicular to level curve - question

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Discussion Overview

The discussion revolves around the proof that the gradient of a function is perpendicular to the level curve of that function. Participants explore the implications of the proof presented in a calculus textbook, questioning the necessity of specific parameter values in the proof and seeking a more intuitive understanding of the concept.

Discussion Character

  • Exploratory
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant questions the need to specify the values of x(0) and y(0) in the proof, suggesting that if the parameterization is valid for all t, the derivative of f should be zero for all t on the level curve.
  • Another participant agrees, stating that since f(x(t), y(t)) is constant for all t on the level curve, it should suffice to express the derivative as zero without specific parameter values.
  • A different participant challenges the notion that specifying t=0 is a restriction, arguing that it does not limit the types of curves being studied.
  • Some participants express a desire for a more intuitive proof, indicating that the details in the textbook feel unnecessary or overly meticulous.
  • One participant humorously suggests that the author's attention to detail could be seen as a virtue, despite the perceived nitpicking.

Areas of Agreement / Disagreement

Participants generally agree that the specification of certain values in the proof may be unnecessary, but there is no consensus on whether this detail is a restriction or simply a stylistic choice. The discussion remains unresolved regarding the need for a more intuitive proof.

Contextual Notes

Some participants express uncertainty about the implications of the specified parameter values and their relevance to the generality of the proof. There is a lack of clarity on how these details affect the understanding of the concept.

raxAdaam
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Hi -

I was reading Adams' "Calculus: A Complete Course" (6th edition) and he offers the following proof that the gradient of a function:

Let \mathbf{r} = x(t)\mathbf{i} + y(t)\mathbf{j} be a parametriazation of the level curve of f such that x(0) = a and y(0) = b. Then for all t near 0, f\left( x(t), y(t)\right) = f(a,b). Differentiating this equation with respect to t using the chain rule, we obtain:

f_1\frac{dx}{dt}+ f_2\frac{dy}{dt} = 0

At t=0 this says that \nabla f(a,b) \cdot \frac{d\mathbf{r}}{dt}\Big|_{t=0}=0, that is, \nabla f is perpendicular to the tangent vector \frac{d\mathbf{r}}{dt} to the level curve at (a,b).

I'm just wondering why the emphasis on specifying the values of x(0) and y(0), or even the need to specify t = 0 in the last statement? If \mathbf{r} is a parameterization of the level curve, then isn't the derivative of f zero for all values of t? Why not go for the more general statement?

I guess I just don't find the proof very satisfying. Obviously I don't doubt it, but does anyone know a more intuitive proof? I'm teaching the concept shortly and always appreciate bringing an intuitive approach. Usually I try to make connections to single variable, but that's not possible here …

Thanks in advance,

Rax
 
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I agree; there seems to be no reason to have a, b, or t = 0. If x(t), y(t) is parameterization of the level curve for some values of t, then the value of f(x(t), y(t)) is a constant for all t that correspond to being on the level curve. It should be okay to write

\frac{df}{dt} = \nabla f \cdot \frac{d\vec{r}}{dt} = 0
 
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How is the book's presentation a restriction of the statement's generality?

Having t=0 being a point on the parametrized curve is no restriction on the types of curves studied.
Having x(0) equal some arbitrary number "a" and y(0) some arbitrary number "b" do not represent restrictions either.
 
@arildno thanks for your comment. I realize that they do not represent restrictions, I guess I just feel that they are **suggestive** of restrictions because (ISFAIA) it is unnecessary. I also just don't understand why he would bother with those details?
 
@MisterX - I thought I posted a quick thank you for sharing your thoughts. I really appreciate your weighing into let me know I'm not alone in this sentiment :D.
 
raxAdaam said:
I also just don't understand why he would bother with those details?

Because he is nitpicky.
Nitpickiness is a virtue, not a vice. :smile:
 

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